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3 years ago

14

List three things you would need to consider to determine whether or not a chemical system is at equilibrium?

2 answers:

Vitek1552 [10]3 years ago

6 0

First of all you need a chemical system ie a system in which there are at least two reactants to start with. Then there needs to be a reaction between the reactants so that products are being created. Finally it needs to be determined at what point there are no more products being created, and that then should represent equilibrium.

olganol [36]3 years ago

3 0

Chemical system is at equilibrium<span> if both reactants and products are present in concentrations which have no further tendency to change with time. To determine whether or not a chemical system is at equilibrium the following things need to be taken into consideration:
1. If the system is open, the chemical system is 100% not in equilibrium. (</span><span>Equilibrium may only be obtained in a closed system).
2. If t</span><span>he forward and reverse </span>reactions are happening at equal rates, then the system is at <span>equilibrium.
3. If t</span>he products and reactants are present in equal concentrations, then the system is at <span>equilibrium.</span>

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A chemist dilutes 185 of the 3.0 M solution with water until a new volume of 750 is obtained. Calculate the new concentration

svlad2 [7]

Answer:

0.74M

Explanation:

Step 1 :

Data obtained from the question.

Initial concentration (C1) = 3M

Initial volume (V2) = 185mL

Final volume (V2) = 750mL

Final concentration (C2) =..?

Step 2:

Determination of the new concentration of the solution.

The new concentration of the solution can be obtained by using the dilution formula as shown below:

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Water has a boiling point of 100.0°C and a Kb of 0.512°C/m. What is the boiling

Reil [10]

Answer:

The boiling point of a 8.5 m solution of Mg3(PO4)2 in water is<u> 394.91 K.</u>

Explanation:

The formula for molal boiling Point elevation is :

$\Delta T_{b} = iK_{b}m$

$\Delta T_{b}$ = elevation in boiling Point

$K_{b}$ = Boiling point constant( ebullioscopic constant)

m = molality of the solution

<em>i =</em> Van't Hoff Factor

Van't Hoff Factor = It takes into accounts,The abnormal values of Temperature change due to association and dissociation .

In solution Mg3(PO4)2 dissociates as follow :

$Mg_{3}(PO_{4})_{2}\rightarrow 3Mg^{2+} + 2 PO_{4}^{3-}$

Total ions after dissociation in solution :

= 3 ions of Mg + 2 ions of phosphate

Total ions = 5

<em>i =</em> Van't Hoff Factor = 5

m = 8.5 m

$K_{b}$ = 0.512 °C/m

Insert the values and calculate temperature change:

$\Delta T_{b} = iK_{b}m$

$\Delta T_{b} = 5\times 0.512\times 8.5$

$\Delta T_{b} = 21.76 K$

Boiling point of pure water = 100°C = 273.15 +100 = 373.15 K

$\Delta T_{b} = T_{b} - T_{b}_{pure}$

$T_{b}_{pure}$ = 373.15 K[/tex]

21.76 = T - 373.15

T = 373.15 + 21.76

T =394.91 K

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