List three things you would need to consider to determine whether or not a chemical system is at equilibrium?

2 answers:

6 0

First of all you need a chemical system ie a system in which there are at least two reactants to start with. Then there needs to be a reaction between the reactants so that products are being created. Finally it needs to be determined at what point there are no more products being created, and that then should represent equilibrium.

olganol [36]2 years ago

3 0

Chemical system is at equilibrium if both reactants and products are present in concentrations which have no further tendency to change with time. To determine whether or not a chemical system is at equilibrium the following things need to be taken into consideration:
1. If the system is open, the chemical system is 100% not in equilibrium. (Equilibrium may only be obtained in a closed system).
2. If the forward and reverse reactions are happening at equal rates, then the system is at equilibrium.
3. If the products and reactants are present in equal concentrations, then the system is at equilibrium.

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The. bond dissociation enthalpies of the H-H bond and the H-Cl bond are 435 kJ mol^-1 and 431 kJ mol^-1, respectively. The ΔHfO

Novay_Z [31]

The bond dissociation energy of the Cl - Cl bond is -958 kJ mol^-1.

<h3>What is the dissociation enthalpy?</h3>

Given that;

H-H bond energy = 435 kJ mol^-1

H-Cl bond energy = 431 kJ mol^-1

ΔHfO of HCL(g) = -92kJ mol^-1

Bond dissociation enthalpy of the Cl-Cl bond = x

-92 = 435 + 431 + x

x = -92 - (435 + 431)

x = -958 kJ mol^-1

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castortr0y [4]

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2 years ago

If you eat 3 apples. How many apples do you have?

Ugo [173]

Answer:

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Explanation:

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2 years ago

A sample of nitrogen gas has the temperature drop from 250.°c to 150.°c at constant pressure. what is the final volume if the in

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Charles law gives the relationship between temperature of gas and volume of gas.
It states that for a fixed amount of gas, temperature is directly proportional to volume of gas.
V / T = k
where V- volume , T - temperature and k - constant
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parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation.
T1 = 250 °C + 273 = 523 K
T2 = 150 °C + 273 = 423 K
Substituting the values in the equation,

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3 years ago