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Mamont248 [21]
3 years ago
14

List three things you would need to consider to determine whether or not a chemical system is at equilibrium?

Chemistry
2 answers:
Vitek1552 [10]3 years ago
6 0
First of all you need a chemical system ie a system in which there are at least two reactants to start with. Then there needs to be a reaction between the reactants so that products are being created. Finally it needs to be determined at what point there are no more products being created, and that then should represent equilibrium.
olganol [36]3 years ago
3 0
Chemical system is at equilibrium<span> if both reactants and products are present in concentrations which have no further tendency to change with time. To determine whether or not a chemical system is at equilibrium the following things need to be taken into consideration:
1. If the system is open, the chemical system is 100% not in equilibrium. (</span><span>Equilibrium may only be obtained in a closed system).
2. If t</span><span>he forward and reverse </span>reactions are happening at equal rates, then the system is at <span>equilibrium.
3. If t</span>he products and reactants are present in equal concentrations, then the system is at <span>equilibrium.</span>
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Calculate how many grams of the first reactant are necessary to completely react with 17.3 g of the second reactant. the reactio
soldier1979 [14.2K]

Taking into account the reaction stoichiometry, 16.611 grams of Na₂CO₃ are necessary to completely react with 17.3 g of CuCl₂.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

Na₂CO₃ + CuCl₂  → CuCO₃ + 2 NaCl

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • Na₂CO₃: 1 mole
  • CuCl₂: 1 mole
  • CuCO₃: 1 mole
  • NaCl: 2 moles

The molar mass of the compounds is:

  • Na₂CO₃: 129 g/mole
  • CuCl₂: 134.45 g/mole
  • CuCO₃: 123.55 g/mole
  • NaCl: 58.45 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • Na₂CO₃: 1 mole ×129 g/mole= 129 grams
  • CuCl₂: 1 mole ×134.45 g/mole= 134.45 grams
  • CuCO₃: 1 mole ×123.55 g/mole= 123.55 grams
  • NaCl: 2 mole ×58.45 g/mole=116.9 grams

<h3>Mass of CuCl₂ required</h3>

The following rule of three can be applied: If by reaction stoichiometry 134.35 grams of CuCl₂ react with 129 grams of Na₂CO₃, 17.3 grams of CuCl₂ react with how much mass of Na₂CO₃?

mass of Na₂CO₃= (17.3 grams of CuCl₂× 129 grams of Na₂CO₃)÷ 134.35 grams of CuCl₂

<u><em>mass of Na₂CO₃= 16.611 grams</em></u>

Finally, 16.611 grams of Na₂CO₃ is required.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

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