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lutik1710 [3]
3 years ago
11

The two pieces of clothing have ____ charges and they _____ each other.

Chemistry
2 answers:
Masteriza [31]3 years ago
7 0

like charges and they repel each other.

Explanation:

The two pieces of clothing will have like charges and they repel each other. Similar substances often loose and gain electrons the same way.

  • The two pieces of clothes will have the same charge on them.
  • According to Coulomb's law, unlike charges attracts while like charges repel one another.
  • Since the charges on the clothes are the same, they will repel one another.

Learn more:

Peep into intermolecular attraction brainly.com/question/6717479

Ionic bonds brainly.com/question/7007192

#learnwithBrainly

Mashutka [201]3 years ago
4 0

Answer:

The two pieces of clothing have like charges and they repel each other.

Explanation:

like charges and they repel each other.

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PLEASE HELP!!!!!!!!!
andreev551 [17]

The average atomic mass of the imaginary element : 47.255 amu

<h3>Further explanation  </h3>

The elements in nature have several types of isotopes  

Isotopes are elements that have the same Atomic Number (Proton)  

Atomic mass is the average atomic mass of all its isotopes  

Mass atom X = mass isotope 1 . % + mass isotope 2.% ..

isotope E-47 47.011 amu, 87.34%

isotope E-48 48.008 amu, 6.895

isotope E-49 50.009 amu, 5.77%

The average atomic mass :

\tt avg~mass=0.8734\times 47.011+0.06895\times 48.008+0.0577\times 50.009\\\\avg~mass=41.059+3.310+2.886\\\\avg~mass=47.255~amu

5 0
2 years ago
if 30.0L of oxygen are cooled from 200 degrees celsius to 1 degree celsius at constant pressure, what is the new volume of oxyge
Sergio039 [100]

Answer: 18.65L

Explanation:

Given that,

Original volume of oxygen (V1) = 30.0L

Original temperature of oxygen (T1) = 200°C

[Convert temperature in Celsius to Kelvin by adding 273.

So, (200°C + 273 = 473K)]

New volume of oxygen V2 = ?

New temperature of oxygen T2 = 1°C

(1°C + 273 = 274K)

Since volume and temperature are given while pressure is held constant, apply the formula for Charle's law

V1/T1 = V2/T2

30.0L/473K = V2/294K

To get the value of V2, cross multiply

30.0L x 294K = 473K x V2

8820L•K = 473K•V2

Divide both sides by 473K

8820L•K / 473K = 473K•V2/473K

18.65L = V2

Thus, the new volume of oxygen is 18.65 liters.

5 0
3 years ago
What volume (in L) of oxygen will be required to produce 77.4 L of water vapor in the reaction below?
Inga [223]

Answer:

90.3 L

Explanation:

Given data:

Volume of water produced = 77.4 L

Volume of oxygen required = ?

Solution:

Chemical equation:

2C₂H₆ + 7O₂  →  4CO₂ + 6H₂O

It is known that,

1 mole = 22.414 L

There are 7 moles of oxygen = 7×22.414 = 156.9 L

There are 6 moles of water = 6×22.414 = 134.5 L

Now we will compare:

                               H₂O           :              O₂    

                               134.5         :              156.9

                                 77.4         :             156.9/134.5×77.4 =90.3 L

So for the production of 77.4 L water 90.3 L oxygen is required.

8 0
3 years ago
6. How will you obtain ? (a) Magnesium oxide from magnesium. (b) Silver chloride from silver nitrate. (c) Nitrogen dioxide from
Reil [10]

Answer:

a) reaction with oxygen

2mg +o2---------2mgo

b) Agno3+NaCl ----------AgCl+NaNo3

8 0
2 years ago
Zinc metal reacts with copper sulfate through the following
morpeh [17]

Answer:

26.9

Explanation:

5 0
2 years ago
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