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malfutka [58]
4 years ago
10

Julia worked 15 hours more than James last month. If Julia worked 8 hours for every 4 hours that James worked how many how’s did

they each work
Mathematics
1 answer:
Svetlanka [38]4 years ago
5 0

Answer:

Step-by-step explanation:

Julia worked 8 hours for every 4 hours that James worked.  This  shows that for every hour James work, Julia works double the time ie . 2 hours.

Julia worked 15 hours more than James last month.

Julia worked 30hours and James worked 15 hours

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A scuba diver dives 750 feet underwater, swims up 375 feet, and then swims down 225 feet. After all of that where is the diver a
Hatshy [7]

Answer:

a grave

Step-by-step explanation:

he died...........

4 0
3 years ago
1
hoa [83]

Answer:

10x greater

Step-by-step explanation:

Two friends let’s say their names are

Molly                         Polly

130 points                  83 points

Molly‘s 3 in her 130 is is the tens place  

here a chart:     ones    Tens.        Hundreds.     thousands.  

                         <u>1</u>265      1<u>2</u>65.         12<u>6</u>5.              126<u>5</u>

now let’s go back to Molly and Polly. The 3 in 130 is one place above the 3 in 83 and this ,my friend, technically means it is only 10x greater

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7 0
3 years ago
Find the value of the variable and the measure of each labeled angle
ololo11 [35]
Since the two angles that you have are vertical angles, we know that vertical angles are congruent, so you have to set them to equal each other.

x+24=5x-36
-4x+24=-36
-4x=-60
x=15

We now have the value of x so now we plug it in for each expression of each angle.

x+24=?
15+24=39

5x-36=?
5(15)-36=?
75-36=39
8 0
3 years ago
I want to pour a concrete slab in my backyard with an area of 370 ft2 to put a basketball goal. If the length of the slab is 23
Soloha48 [4]
A=lw A=370 l=6w-23
370=w(6w-23)
6w^2-23w=370
6w^2-23w-370
Works out to
(W-10) pick this one
+10
W=10
or
(6w+37) is not the answer to choose
-37
6w=-37
/6 /6
W=-6.17


A) 10
B) 10
C) 37
8 0
3 years ago
An automobile travels past the farmhouse at a speed of v = 45 km/h. How fast is the distance between the automobile and the farm
yulyashka [42]

Answer:

\frac{ds}{dt} = 39.586 km/h

Step-by-step explanation:

let distance between farmhouse and road is 2 km

From diagram given

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By using Pythagoras theorem

s^2 = 2^2 +p^2

differentiate wrt t

we get

\frac{d}{dt} s^2 = \frac{d}{dt} (4 + p^2)

2s \frac{ds}{dt}  =2p \frac{dp}{dt}

\frac{ds}{dt} = \frac{p}{s}\frac{dp}{dt}

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putting p = 3.7 km

\frac{ds}{dt} = \frac{3.7}{\sqrt{3.7^2 +4}} 45

\frac{ds}{dt} = 39.586 km/h

3 0
4 years ago
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