All categories

2 years ago

What are the factors of 19

Mathematics

2 answers:

madam [21]2 years ago

8 0

1 and 19, 19 is a prime number.

ivanzaharov [21]2 years ago

5 0

its only 1, bc 19 is a prime number

You might be interested in

PLS Helps A box had a length of 23 foot, a width of 12 foot and a height of 2 feet. What is the volume of this box?

vodka [1.7K]

Answer:

23 times 12 times 2= 552. but i dont understand the last part so think there is a typo

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Allie noticed that to get her test grade, she could take Valerie's grade, multiply it by 2 and subtract 15. If Valerie's test gr

kolbaska11 [484]

Answer is c) 2x - 15 because x is Valerie's grade

Allie's grade is <span>taking Valerie's grade, multiply it by 2 and subtract 15</span>

4 0

2 years ago

Consider the line integral Z C (sin x dx + cos y dy), where C consists of the top part of the circle x 2 + y 2 = 1 from (1, 0) t

pashok25 [27]

Direct computation:

Parameterize the top part of the circle $x^2+y^2=1$ by

$\vec r(t)=(x(t),y(t))=(\cos t,\sin t)$

with $0\le t\le\pi$ , and the line segment by

$\vec s(t)=(1-t)(-1,0)+t(2,-\pi)=(3t-1,-\pi t)$

with $0\le t\le1$ . Then

$\displaystyle\int_C(\sin x\,\mathrm dx+\cos y\,\mathrm dy)$

$=\displaystyle\int_0^\pi(-\sin t\sin(\cos t)+\cos t\cos(\sin t)\,\mathrm dt+\int_0^1(3\sin(3t-1)-\pi\cos(-\pi t))\,\mathrm dt$

$=0+(\cos1-\cos2)=\boxed{\cos1-\cos2}$

Using the fundamental theorem of calculus:

The integral can be written as

$\displaystyle\int_C(\sin x\,\mathrm dx+\cos y\,\mathrm dy)=\int_C\underbrace{(\sin x,\cos y)}_{\vec F}\cdot\underbrace{(\mathrm dx,\mathrm dy)}_{\vec r}$

If there happens to be a scalar function $f$ such that $\vec F=\nabla f$ , then $\vec F$ is conservative and the integral is path-independent, so we only need to worry about the value of $f$ at the path's endpoints.

This requires

$\dfrac{\partial f}{\partial x}=\sin x\implies f(x,y)=-\cos x+g(y)$

$\dfrac{\partial f}{\partial y}=\cos y=\dfrac{\mathrm dg}{\mathrm dy}\implies g(y)=\sin y+C$

So we have

$f(x,y)=-\cos x+\sin y+C$

which means $\vec F$ is indeed conservative. By the fundamental theorem, we have

$\displaystyle\int_C(\sin x\,\mathrm dx+\cos y\,\mathrm dy)=f(2,-\pi)-f(1,0)=-\cos2-(-\cos1)=\boxed{\cos1-\cos2}$

3 0

2 years ago

100min to 2h as a ratio

Usimov [2.4K]

Answer:

100:2 or 50:1

Step-by-step explanation:

Hope this helps!

4 0

2 years ago

Read 2 more answers

A rectangle has an area of 36 square units. As the length and the width change, what do you know about their product? Is this le

m_a_m_a [10]

Area = 36 = length*width

Then, while the area is constant the product length*width is constant.

Length and area are inversely related.

That means that to keep the same product (area), length vary in inverse proportion to width.

If you increase length, widht has to decrease to satisfy this relation:

width = 36/length

Of course, you can also say: length = 36 / width.

5 0

2 years ago