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makvit [3.9K]
3 years ago
7

Given: △ABC,

Mathematics
1 answer:
Alexxandr [17]3 years ago
7 0

we are given

△ABC

we can use area of triangle formula

A=\frac{1}{2} AB*BC*sin(B)

we have

AB=6

BC=10

m∠B=120°

so, we can plug it

A=\frac{1}{2} 6*10*sin(120)

A=\frac{1}{2} *60*\frac{\sqrt{3} }{2}

A=15\sqrt{3}..............Answer


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Answer:

Step-by-step explanation:

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It becomes undefined at x = 0 (I will show both curves below).

That is not what has been given. The graph you have been given becomes undefined at x = - 1 , so the equation of the curve (so far) y = 1/(x + 1)

Now we have to worry about the y intercept. When x = 0, y = 4. That can be accomplished in two ways

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All three of these will give a value of y = 4 when x = 0. But you have 1 problem left. What happens as x goes to say 5.

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The value of C will give y = 1/(5 + 1) + 3 which gives 3 1/5 which also does not work.

Only B works. y = 2/(5+1) + 2 = 2/6 + 2 = 2 1/3 which is a little above the horizontal asymptote.

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==================================
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<em>"Associate with people who are likely to improve you."</em>
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