Question

Given: △ABC,

Answer 1

we are given

△ABC

we can use area of triangle formula

$A=\frac{1}{2} AB*BC*sin(B)$

we have

AB=6

BC=10

m∠B=120°

so, we can plug it

$A=\frac{1}{2} 6*10*sin(120)$

$A=\frac{1}{2} *60*\frac{\sqrt{3} }{2}$

$A=15\sqrt{3}$..............Answer