Question

Quadrilateral ABCD has the following vertices.

Answer 1

A(-5,5)
B(4,5)
C(2,0)
D(-5,-2)

AB,BC,CD,DA

AB = [4-(-5)),5-5]=[9,0]
Lenght  $AB= \sqrt{9^2+0^2}= \sqrt{81} =9$

BC = [2-4,0-5]=[-2,-5]
Lenght  $BC=\sqrt{(-2)^2+(-5)^2}=\sqrt{4+25}=\sqrt{29}$

CD = [-5-2,-2-0]=[-7,-2]
Lenght  $CD=\sqrt{(-7)^2+(-2)^2}=\sqrt{49+4}=\sqrt{53}$

DA =[-5-(-5),-2-5]=[0,-7]
Lenght $DA=\sqrt{0^2+(-7)^2}=\sqrt{49}=7$

sorted from longest to shortest:
AB, CD,DA,BC
$\sqrt{81}, \sqrt{53}, \sqrt{49}, \sqrt{29}$