Answer:
Volume of stock 50X TAE buffer required is 4 mL;
Volume of distilled water needed = 196 mL
The researcher will measure 4 mL of the stock 50X TAE solution using a pipette into a 250 mL volumetric flask. The researcher will then add 196 ml of distilled water to make it up to the 200 ml mark.
Explanation:
The following values are given: initial concentration, final concentration and final volume
Initial concentration,C₁ = 50X
Final concentration, C₂ = 1X
Final volume, V₂ = 200 mL
Initial volume, V₁ = ?
Using C₁V₁ = C₂V₂
V₁ = C₂V₂/C₁
V₁ = 1X * 200 mL/50X
V₁ = 4 mL
Therefore, volume of stock 50X TAE buffer required is 4 mL
Volume of distilled water needed = 200 mL - 4 mL
Volume of distilled water needed = 196 mL
The researcher will measure 4 mL of the stock 50X TAE solution using a pipette into a 250 mL volumetric flask. The researcher will then add 196 ml of distilled water to make it up to the 200 ml mark.
Answer:
it is either A or B but I think a
The independent variable is if the plants have light or not.
Answer:
Both parents are heterozygous i.e. Aa
Explanation:
This question involves a single gene coding for melanin pigmentation in humans. The dominant trait is normal pigmentation while the recessive trait is albinism. Note that, recessive trait means that both alleles must contain the same recessive alleles.
Let's say that the allele for normal pigmentation (presence of melanin) is A while the allele for albinism (without melanin) is a. The allele for normal pigmentation (A) is dominant over the allele for albinism (a). This means that allele "A" will always mask the phenotypic expression of allele "a" in a heterozygous state.
If a man and a woman with normal pigmentation gives birth to an albino child, it means the parents have the albino allele being masked in their genotype. In other words, both parents are heterozygous i.e Aa. If the two parents come together (see punnet square), gametes A and a will be produced by each parent.
The recessive alleles (a) of each parent's gamete combines to form a child that possesses the recessive trait (aa). Hence, the genotype of the parents will be HETEROZYGOUS (Aa).
Atomic Mass equals Protons + Neutrons, so 6+7=13
<span>The atomic mass of an element whose atoms consist of six protons, seven neutrons, and six electrons is 13</span>