If you adjusted the frequency to be lower than the resonant frequency, would the voltage have been leading ahead of or lagging b
ehind the current? Explain
1 answer:
Answer:
current will lead the voltage
Explanation:
From the bellow figure we can see the plot between the frequency and impedance
From the figure it is clear that when the frequency is less than the resonance frequency then the impedance decreases as the frequency increases it is possible only when impedance is capacitive in nature.
As the impedance is capacitive in nature so current will lead than the voltage
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Answer:
F = 19.1 N
Explanation:
To find the force exerted by the string on the block you use the following formula:
(1)
k: spring constant = 95.5 N/m
x: displacement of the block from its equilibrium position = 0.200 m
you replace the values of k and x in the equation (1):
Hence, the force exterted on the block is 19.1 N