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elena55 [62]
4 years ago
14

If you adjusted the frequency to be lower than the resonant frequency, would the voltage have been leading ahead of or lagging b

ehind the current? Explain

Physics
1 answer:
tatyana61 [14]4 years ago
4 0

Answer:

current will lead the voltage

Explanation:

From the bellow figure we can see the plot between the frequency and impedance

From the figure it is clear that when the frequency is less than the resonance frequency then the impedance decreases as the frequency increases it is possible only when impedance is capacitive in nature.

As the impedance is capacitive in nature so current will lead than the voltage

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A car travels at 15 m/s for 30 minutes. How far did it travel?
Brilliant_brown [7]

Answer:

27000 meters

Explanation:

15 x 60 x 30

5 0
3 years ago
What quantity is multiplied by the hydraulic lift system of a dump truck?
ELEN [110]
A. Force
Hope this helps!!
8 0
3 years ago
A helium-neon laser emits light of wavelength 632.8 nm and has a power output of 16 mw. how many photons are emitted per second
NemiM [27]
The power of the laser is
P=16 mW=0.016 W
by using the relationship between power, energy and time, we can find the energy delivered by the laser in 1 second:
E=Pt=(0.016 W)(1 s)=0.016 J

The frequency of the photons of this light is given by
f= \frac{c}{\lambda}= \frac{3\cdot 10^8 m/s}{632.8 \cdot 10^{-9} m} =4.74 \cdot 10^{14} Hz
and the energy of a single photon is
E_1=hf=(6.6\cdot 10^{-34} Js)(4.74 \cdot 10^{14} Hz)=3.13 \cdot 10^{-19} J

In order to find the number of photons emitted per second, we must divide the total energy emitted by the laser by the energy of a single photon, and we get:
N= \frac{E}{E_1}= \frac{0.016 J}{3.13 \cdot 10^{-19}J} =5.11 \cdot 10^{16} photons
7 0
3 years ago
The conductors that carry the current to electrical devices and ? equipment are the heart of all electrical systems. There are a
MariettaO [177]

Answer:

utilization / effects

Explanation:

Utilization equipment are those equipment that makes use of electric energy for the purpose of chemical, electronic, lighting, heating, electro-mechanical or other alike purposes. Hence utilization best suits the first question mark in the question. Secondly, there are associated effects when current flows through a conductor, not responses.

5 0
3 years ago
A river with a flow rate of 7 m3/s discharges into a lake with a volume of 9,000,000 m3. The concentration of a particular VOC i
soldi70 [24.7K]

Answer:

The concentration downstream reduces to 0.03463mg/L

Explanation:

Initially let us calculate the time it is required to fill the lake, since for that period of time the pollutant shall remain in the lake before being flushed out.

Thus the detention period is calculated as

t=\frac{V}{Q}\\\\t=\frac{9000000}{7}=1.285\times 10^{6}seconds\\\\\therefore t = 14.872days

Now the concentration of the pollutant after 14.872 days is calculated as

N_{t}=N_{0}e^{-kt}

where

N_{o} is the initial concentration

't' is the time elapsed after which the remaining concentration is calculated

k is the dissociation constant.

Applying values we get

N_{t}=3\times e^{-0.3\times 14.872}

N_{t}=0.03463mg/L

4 0
3 years ago
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