Explanation:
Formula to calculate the electric field of the sheet is as follows.
E = 
And, expression for magnitude of force exerted on the electron is as follows.
F = Eq
So, work done by the force on electron is as follows.
W = Fs
where, s = distance of electron from its initial position
= (0.570 - 0.06) m
= 0.51 m
First, we will calculate the electric field as follows.
E =
= 
= 0.259 N/C
Now, force will be calculated as follows.
F = Eq
= 
= 
Now, work done will be as follows.
W = Fs
= 
= 
Thus, we can conclude that work done on the electron by the electric field of the sheet is .
Degrees of loudness and softness in music are called dynamics. I don’t really have an explanation for this, that’s just what they’re called. I know because I’m a violinist and learned it when I first started playing.
We are asked to solve for the index of refraction and the formula is n = c/v where "n" represents the index of refraction, "c" represents the speed of light in the vacuum while "v" represents the speed of another medium.
In the problem, we have the given values below:
c = 3 x 10^8 m/s
v = 2 x 10^8 m/s
n =?
Solving for n, we have the solution below:
n = 3x10^8 / 2x10^8
n = 1.5
The answer is 1.5 for the index of refraction.
KE= .5*M*V^2
.5*.06*50^2
=75 joules
Answer:
frequency is 195.467 Hz
Explanation:
given data
length L = 4.36 m
mass m = 222 g = 0.222 kg
tension T = 60 N
amplitude A = 6.43 mm = 6.43 × 
m
power P = 54 W
to find out
frequency f
solution
first we find here density of string that is
density ( μ )= m/L ................1
μ = 0.222 / 4.36
density μ is 0.050 kg/m
and speed of travelling wave
speed v = √(T/μ) ...............2
speed v = √(60/0.050)
speed v = 34.64 m/s
and we find wavelength by power that is
power = μ×A²×ω²×v / 2 ....................3
here ω is wavelength put value
54 = ( 0.050 ×(6.43 × )²×ω²× 34.64 ) / 2
0.050 ×(6.43 × )²×ω²× 34.64 = 108
ω² = 108 / 7.160 × 
ω = 1228.16 rad/s
so frequency will be
frequency = ω / 2π
frequency = 1228.16 / 2π
frequency is 195.467 Hz
