If you adjusted the frequency to be lower than the resonant frequency, would the voltage have been leading ahead of or lagging b
ehind the current? Explain
1 answer:
Answer:
current will lead the voltage
Explanation:
From the bellow figure we can see the plot between the frequency and impedance
From the figure it is clear that when the frequency is less than the resonance frequency then the impedance decreases as the frequency increases it is possible only when impedance is capacitive in nature.
As the impedance is capacitive in nature so current will lead than the voltage
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Answer:
The value is
Explanation:
From the question we are told that
The first amplitude of the wave is
The first depth is
The second amplitude is
The second depth is
Generally from the spatial wave equation we have
=>
So considering the ratio of the equation for the two depth
=>
=>
=>