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Leokris [45]
3 years ago
13

To calculate acceleration you must know both the objects velocity and_____

Physics
1 answer:
amm18123 years ago
8 0

You need to know the time as well.

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How does the thermosphere,(the outer most layer) help earth?
Neko [114]
The THERMOSPHERE is the layer of the Earth's Atmosphere directly above the Mesosphere and directly below the Exophere.(I know its not much but,I hope it helps you)
7 0
3 years ago
What is the ratios of sodium hydroxide
Katena32 [7]
Clarify what you mean by ratios?
8 0
3 years ago
A converging lens of focal length 20 cm is placed in contact with, and to the left of, a diverging lens of focal length 30 cm. I
scZoUnD [109]

Answer:

Magnification will be equal to 3

Explanation:

We have given focal length of the converging lens F_1=20cm

Focal length of the diverging lens F_2=30cm

Object is placed 40 cm to the length of the converging lens d = 40 cm

Combination of the focal length will be equal to

\frac{1}{F}=\frac{1}{F_1}+\frac{1}{F_2}

\frac{1}{F}=\frac{1}{20}+\frac{1}{-30}=\frac{1}{20}-\frac{1}{30}=\frac{1}{60}

F = 60 cm

So combination of the focal length will be 60 cm

Magnification is given by

M=\frac{F}{F-d}=\frac{60}{60-40}=3

So magnification will be equal to 3

3 0
3 years ago
At what rate is soda being sucked out of a cylindrical glass that is 6 in tall and has radius of 2 in? The depth of the soda dec
evablogger [386]

Answer:

The soda is being sucket out at a rate of 3.14 cubic inches/second.

Explanation:

R= 2in

S= π*R²= 12.56 inch²

rate= 0.25 in/sec

rate of soda sucked out= rate* S

rate of soda sucked out=  3.14 inch³/sec

4 0
3 years ago
A photographer wants to determine the color of light he can use in the darkroom that will not expose the films he is processing.
Sonbull [250]

For a photographer that wishes to determine the color of light that he can use in a dark room that will not expose the films he is processing, having used a Blue Incandescent bulb, he should proceed to use a Red Incandescent bulb for the next trial.

The photographer in question is performing an experiment. For these kinds of experiments it is important to identify the variables present, which can be of three kinds:

  1. Control variables
  2. Dependent variables
  3. Independent variables

For this experiment, the dependent variable is the exposure of the light onto the films, given that this is what we wish to measure. The independent variable will be the color of the light being used which is what will affect the dependent variable.

The remaining variable must be the control variable. Unlike the previous variables, we can have more than one of these. The control variable is there to make sure that only the dependent variable is affecting the outcome. We do this by keeping the control variable the same through each trial, which is why the photographer should not change the type of bulb in the second experiment, changing only the color of the light.

To learn more visit:

brainly.com/question/1549017?referrer=searchResults

4 0
3 years ago
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