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AlekseyPX
3 years ago
11

Which of the following is the visible part of the spectrum of light?

Physics
2 answers:
mestny [16]3 years ago
6 0
The visible spectrum<span> is portion of the </span>electromagnetic spectrum<span> that is </span>visible <span>to the </span><span>human eye.
</span>gamma rays, <span>sound waves, </span><span>microwaves are not the part of spectrum of light, whereas color is the portion of spectrum of light.</span>
MissTica3 years ago
6 0

Answer:

Color

Explanation:

The electromagnetic spectrum is a classification of all the types of electromagnetic waves. They are generally classified based on their wavelengths. In order of increasing wavelength, they are:

Gamma rays

X-rays

Ultraviolet

Visible light (colors)

Infrared

Microwaves

Radio waves

These types of waves are characterized by different properties. Not all of them are visible to human eye: in fact, only a small portion of the spectrum is visible to human eye, and this corresponds to the part called visible light, which includes all the colors from violet to red. The wavelengths of this part of the spectrum fall within the range 380 nm - 750 nm approximately.

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Piano tuners tune pianos by listening to the beats between the harmonics of two different strings. When properly tuned, the note
mote1985 [20]

Answer:

Frequency = 658 Hz

Explanation:

The third harmonics of A is,

f_{A}=(3)(440Hz)=1320Hz

The second harmonics of E is,

f_{E}=(2)(659Hz)=1318Hz

The difference in the two frequencies is,

delta_f = 1320 Hz - 1318 Hz = 2 Hz

The beat frequency between the third harmonic of A and the second harmonic of E is,

delta_f = 3f_{A}-2f_{E}

f_{E}=\frac{3f_{A}-delta_f}{2}

We have calculate the frequency of the E string when she hears four beats per second, then

delat_f = 4 Hz

f_{E}=\frac{3(440Hz)-4Hz}{2}

f_{E}=658Hz

Hope this helps!

5 0
3 years ago
A mass of 267 g is attached to a spring and set into simple harmonic motion with a period of 0.176 s. If the total energy of the
Gnoma [55]

Answer:

(a) 7.1 m /sec

(b) 339.9 N/m

(c) 19.91 cm

Explanation:

We have given mass m = 267 gram = 0.267 kg

Time period T = 0.176 sec

Total energy of the oscillating  system = 6.74 J

We know that energy is given by

(a) Ke=\frac{1}{2}mv_{max}^2

6.74=\frac{1}{2}\times 0.267\times v_{max}^2

v_{max}=7.1m/sec

(b) Now \omega =\frac{2\pi }{T}=\frac{2\times 3.14}{0.176}=35.681rad/sec

We know that \omega =\sqrt{\frac{k}{m}}

35.68=\sqrt{\frac{k}{0.267}}

k=339.9N/m

(c) We know that energy is given by

E=\frac{1}{2}KA^2

6.74=\frac{1}{2}\times 339.9\times A^2

A=19.91cm

4 0
3 years ago
The function​ s(t) represents the position of an object at time t moving along a line. Suppose s (2 )equals 146and s (6 )equals
sineoko [7]

Answer:

v(t) = 27 units

Explanation:

The function s(t) represents the position of an object at time t moving along a line such that,

s(2)=146

and

s(6)=254

We need to find the average velocity of the object over the interval of time [2,6]. The velocity of the object is equal to the total distance divided by time. It is given by :

v(t)=\dfrac{s(6)-s(2)}{6-2}

v(t)=\dfrac{254-146}{6-2}

v(t) = 27 units

So, the  average velocity of the object is 27 units. Hence, this is the required solution.

5 0
3 years ago
Which of the statements concerning light are true? The speed of light is the same no matter what material it is traveling throug
wel

Answer:

The statements that are true concerning light are the last three statements:

  • Its propagation direction is perpendicular to both the electric field and the magnetic field.
  • It moves at a constant speed through a vacuum.
  • The speed of light in matter is less than the speed of light in a vacuum.

Explanation:

<em>Light</em> is <em>electromagnetic waves.  </em>

The properties of the electromagnetic waves were established by James Clerk Maxwell.

They included that they are the result of the oscillation of a <em>magnetic field </em>in phase with an <em>electric field</em> which are always is always <em>perpendicular</em> to each other.

Also, the electromagnetic waves propagate at right-angles to the direction of both the magnetic and the electric field,  meaning that they are a type of transverse wave.

Thus, the second statement (<em>"Its propagation direction is parallel to both the electric field and the magnetic field"</em>) is false, and the fourth statement ("Its propagation direction is perpendicular to both the electric field and the magnetic field") is true.

On the other hand, it is a postulate of the special theory of relativity that the speed of light is a constant (absolute value) in vacuum: nothing can travel faster than what light travels in vacuum. Thus, the fifth statement, <em>"It moves at a constant speed through a vacuum"</em> is true.

About the speed of light in matter, it is always less than the speed of light in vacuum. Thus, the first statement, "<em>the speed of light is the same no matter what material it is traveling through</em>", and the third statement "<em>the speed of light in matter is greater than the speed of light in a vacuum"</em> are false; while the last statement, "<em>the speed of light in matter is less than the speed of light in a vacuum</em>" is true.

The explanation on why the speed of light is less in a medium than in vacuum is related with the fact that at nanoscopic level the waves suffer polarization which means deviations from the straighi path, which makes that the net straight propagation is slower.

8 0
4 years ago
If the strength of the magnetic field at A is 200 units and the strength of the magnetic field at B is 50 units, what is the dis
Whitepunk [10]
A is the answer!!!!!!!!!!!!!!!!!!
5 0
3 years ago
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