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cluponka [151]
3 years ago
15

Can anyone give me the description of the element mercury is positioned on the periodic table of elements and a list of other el

ements that have similar properties. I need this ASAP. Thanks.

Physics
1 answer:
garri49 [273]3 years ago
3 0
I hope this helps you good luck

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What is the smallest or most specific level of organization you and your neighbors are have in common
kow [346]
We have the same house
3 0
3 years ago
What type of quantity is specified by direction and magnitude?
Kaylis [27]

Answer:

A vector is any quantity with both magnitude and direction. Other examples of vectors include a velocity of 90 km/h east and a force of 500 newtons straight down.

Explanation:

7 0
4 years ago
A 1.2-kg mass is projected from ground level with a velocity of 30 m/s at some unknown angle above the horizontal. A short time
Dmitriy789 [7]

Answer:

K_f = 351.84 J

Explanation:

Using the conservation of energy K:

E_i = E_f

so:

\frac{1}{2}mv^2 = K_f + mgh

where m is the mass, v the initial velocity, K_f is the kinetic energy of the mass as it clears the fence, g the gravity and h the altitude.

Then, replacing values, we get:

\frac{1}{2}(1.2kg)(30m/s)^2 = K_f + (1.2kg)(9.8m/s^2)(16m)

solving for K_f:

K_f = 351.84 J

3 0
3 years ago
A bird has a mass of 0.8 kg and flies at a speed of 11.2 m/s. How much kinetic energy does the bird have?
riadik2000 [5.3K]
The kinetic energy of an object is directly proportional to its mass and the square of its velocity

KE = 1/2 (mv²)

KE = Kinetic Energy
m = mass in kg
v = velocity in m/s

Given:

m = .8 kg
v =  11.2 m/s

Substitute:

KE = 1/2 (.8)(11.2²)
KE = 50.18 J
7 0
3 years ago
Read 2 more answers
1pt A cannon fires a 5-kg ball horizontally from a
Klio2033 [76]

Answer: Both cannonballs will hit the ground at the same time.

Explanation:

Suppose that a given object is on the air. The only force acting on the object (if we ignore air friction and such) will be the gravitational force.

then the acceleration equation is only on the vertical axis, and can be written as:

a(t) = -(9.8 m/s^2)

Now, to get the vertical velocity equation, we need to integrate over time.

v(t) = -(9.8 m/s^2)*t + v0

Where v0 is the initial velocity of the object in the vertical axis.

if the object is dropped (or it only has initial velocity on the horizontal axis) then v0 = 0m/s

and:

v(t) = -(9.8 m/s^2)*t

Now, if two objects are initially at the same height (both cannonballs start 1 m above the ground)

And both objects have the same vertical velocity, we can conclude that both objects will hit the ground at the same time.

You can notice that the fact that one ball is fired horizontally and the other is only dropped does not affect this, because we only analyze the vertical problem, not the horizontal one. (This is something useful to remember, we can separate the vertical and horizontal movement in these type of problems)

7 0
3 years ago
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