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3 years ago

A beam of light has a wavelength of 506 nanometers. What is the frequency of the light

Physics

1 answer:

Fofino [41]3 years ago

8 0

The wavelength of 506nm can be seen as green

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Eric, Sheena, and Yael are playing a game. Eric has half as many points as Sheena. Sheena has two fewer points than Yael. Togeth

nexus9112 [7]

Lets say that:

Eric is E

Sheena is S

Yael is Y

We know that S+2=Y, E= 1/S and that E+S+Y=52. So, we can insert S+2=Y and E= 1/S into our other equation, which would bring us to (1/2S)+(S+2)+S=52. This is equal to 1/2S+S+2+S=52. We then use algebra to get the answer:

Given:

S+2=Y

E=1/S

E+Y+S=52

Equation:

1/2S+S+2+S=52

1/2S+S+S=52

2.5S=50

S=50/2.5

S=20

And since Yael has 2 more points then Yael then we do 20+2 and get 22.

Hope this helps! <3

6 0

3 years ago

The dimensional formula of√(energy/) √mass is same as that of __________.

11Alexandr11 [23.1K]

Answer:

D. Velocity

Explanation:

Energy Dimensional Analysis

The kinetic energy (K) can be calculated by the formula:

$\displaystyle K=\frac{1}{2}mv^2$

Where:

m = mass of the object

v = speed at which the object moves

Solving for v:

$\displaystyle v=\sqrt{\frac{2E}{m}}$

Or, equivalently:

$\displaystyle v=\frac{\sqrt{2E}}{\sqrt{m}}}$

In dimensional terms, the quotient of the square roots of the energy and the mass is equivalent to the dimensions of the velocity (or speed),

D. Velocity

7 0

3 years ago

NEED THE ANSWER PLZ What are lanthanides?

geniusboy [140]

It is the the ecrins of light

5 0

3 years ago

A 763 kg car moving at 26 m/s brakes to a stop. The brakes contain about 15 kg of iron that absorb the energy. What is increase

Neko [114]

Answer:

$\Delta T=38.20^{\circ}$

Explanation:

It is given that,

Mass of the car, m = 763 kg

Speed of the car, v = 26 m/s

Mass of the iron, m' = 15 kg

Specific heat of iron, c = 450 J/kg

When the car is in motion, it will possess kinetic energy. It is given by :

$K=\dfrac{1}{2}mv^2$

$K=\dfrac{1}{2}\times 763\times (26)^2$

K = 257894 J

Since, energy is absorbed by the brakes. The kinetic energy of the car is absorbed by the brakes. So,

$K=mc\Delta T$

$\Delta T$ is the increase in temperature of the brakes

$\Delta T=\dfrac{K}{m'c}$

$\Delta T=\dfrac{257894}{15\times 450}$

$\Delta T=38.20^{\circ}$

So, the increase in temperature of the brakes is 38.20 degrees Celsius. Hence, this is the required solution.

3 0

3 years ago

What does the term "catastrophic event" mean to you

ozzi

Answer:

an event which took place which had such a significant impact.

Explanation:

6 0

3 years ago

Read 2 more answers