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3 years ago

Acceleration: A water rocket can reach a speed of 75 m/s in 0.050 seconds from launch. What is its average acceleration

Physics

1 answer:

kifflom [539]3 years ago

4 0

Answer:

1500 m/s squared

Hope this helps :)

Explanation:

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O 50 squirrels

Explanation:

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2 years ago

Two identical cars, one on the moon and one on earth, are rounding banked curves at the same speed with the same radius and the

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4 years ago

A car is moving southwest at a velocity of 10 meters per second. Five seconds later, it's going 40 meters per second. What was t

Inga [223]

If "during this time" refers to the 5 second interval mentioned above, then the average acceleration is

$\bar a=\dfrac{v-v_0}{t-t_0}=\dfrac{40\,\frac{\mathrm m}{\mathrm s}-10\,\frac{\mathrm m}{\mathrm s}}{5\,\mathrm s-0\,\mathrm s}$

Notice that we took the start time to be the start of the 5 second interval and set that to $t_0=0$ . The starting velocity $v_0$ is the velocity measured at the start of the interval, and $v$ is the velocity measured at its end.

So the average velocity over these 5 seconds is

$\bar a=\dfrac{30\,\frac{\mathrm m}{\mathrm s}}{5\,\mathrm s}=6\,\dfrac{\mathrm m}{\mathrm s^2}$

6 0

4 years ago

A lifeguard on a beach observes that waves have a speed of 2.60 m/s and a distance of 2.50 m between wave crests. What is the pe

Alja [10]

Answer:

T = 0.96 seconds

Explanation:

Given that,

The speed of wave, v = 2.6 m/s

The distance between wave crests, $\lambda=2.5\ m$

We need to find the period of the wave motion. Let T be the period. So,

$v=\dfrac{\lambda}{T}\\\\T=\dfrac{\lambda}{v}\\\\T=\dfrac{2.5}{2.6}\\\\T=0.96\ s$

So, the period of the wave motion is equal to 0.96 seconds.

4 0

3 years ago

A man-made satellite orbits the earth in a circular orbit that has a radius of 32000 km. The mass of the Earth is 5.97e 24 kg. W

Gwar [14]

Answer:

= 3521m/s

The tangential speed is approximately 3500 m/s.

Explanation:

F = m * v² ÷ r

Fg = (G * M * m) ÷ r²

(m v²) / r = (G * M * m) / r²

v² = (G * M) / r

v = √( G * M ÷ r)

G * M = 6.67 * 10⁻¹¹ * 5.97 * 10²⁴ = 3.98199 * 10¹⁴

r = 32000km = 32 * 10⁶ meters

G * M / r = 3.98199 * 10¹⁴ ÷ 32 * 10⁶

v = √1.24 * 10⁷

v = 3521.36m/s

The tangential speed is approximately 3500 m/s.

8 0

4 years ago

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