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2 years ago

If m + 1 is an an even integer which one of the following must be an odd integer ?

Mathematics

2 answers:

Olenka [21]2 years ago

7 0

Answer:

Option C.

Step-by-step explanation:

Even number : A number is called even if it is divisible by 2, i.e., 2, 4, 6,...

Odd number : A number is called odd if it is not divisible by 2, i.e., 1,3,5,...

It is given that m + 1 is an an even integer.

Since alternate numbers are even, therefore m must be an odd number.

If m is odd, then m-1 is even.

2m is divisible by 2, so it is always an even number. So,

2m - 2 is even.

2m+1 is odd.

2m+2 is even.

Since 2m+1 is an odd number, therefore the correct option is C.

AveGali [126]2 years ago

4 0

Answer:

C: 2m + 1

Step-by-step explanation:

If m + 1 is even, then m is odd.

A: m - 1 is even

B: 2m - 2 is even

C: 2m + 1 is odd

D: 2m + 2 is even

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2 years ago

Consider the null hypothesis, H0: µ = 4,000, at the 1% level of significance. If the z-test statistic is calculated to be 6.00,

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Answer:

Option B) Reject null hypothesis

Step-by-step explanation:

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3 years ago

Estimate by rounding the first factor to the nearest ten. Then enter the product.

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Answer:

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3 years ago

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The scheme where you can find the greatest common divisor of two integers by repetitive application of the division algorithm is

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Answer:

False

Step-by-step explanation:

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