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hram777 [196]
3 years ago
13

An arithmetic sequence has a third term of 7 and a fifth term of 13. Write an equation could be used to find the both term of th

e sequence.
Mathematics
1 answer:
levacccp [35]3 years ago
5 0

Answer:

a(n) = 3n - 2.

Step-by-step explanation:

The nth term of an arithmetic sequence = a1 + d(n - 1)  where a1 = the first term and d = the common difference.

So here we  have:

a3 = 7 = a1 + 2d

a5 = 13 = a1 + 4d

Rewriting:

a1 + 4d = 13

a1 + 2d = 7  

Subtracting,  we eliminate a1:

2d = 6

d = 3

and a1 = 7 - 2(3)

= 1.

So our equation we can use to find any term is

a(n) = 1 + 3(n - 1)

a(n) = 1 + 3n - 3

a(n) = 3n - 2 (answer).

Checking :

3rs term = 3(3) - 2 = 7.

5th term = 3(5) - 2 = 13.

First term = 3(1) - 2 = 1.

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Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

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Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

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Part b

Since the distribution for X is normal then the distribution for the sample mean is:

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\bar X \sim N(2.5, \frac{0.03}{\sqrt{10}}=0.00948)

Part c

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See the figure attached the deviation for the sample mean is lower for this reason we have the pattern in the graph attached.

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3 years ago
I could use some help with this problem.
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Step-by-step explanation:

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