It means it will only allow some to go through but not all.
Answer:
41.9(w/w) %
Explanation:
Based on the reaction:
Na₂C₂O₄(s) + 2HCl(aq) → H₂C₂O₄(aq) + 2NaCl(aq)
<em>Where 1 mole of sodium oxalate reacts with 2 moles of HCl</em>
Moles of HCl solution to reach end point are:
44.15mL = 0.04415L ₓ (0.250mol / L) = 0.01104 moles of HCl
As 2 moles of HCl reacts per mole of Na₂C₂O₄:
0.01104mol HCl ₓ (1 mol Na₂C₂O₄ / 2 mol HCl) = <em>5.519x10⁻³ moles Na₂C₂O₄</em> are in the sample.
Molar mass of Na₂C₂O₄ is 134g/mol; thus, mass of 5.519x10⁻³ moles Na₂C₂O₄ is:
5.519x10⁻³ moles Na₂C₂O₄ ₓ (134g / mol) = <em>0.740g of Na₂C₂O₄</em> in the sample.
Thus, percent by mass of sodium oxalate in the sample is:
0.740g of Na₂C₂O₄ / 1.766g ₓ 100 =
<h3>41.9(w/w) %</h3>
The periods inside the Periodic Table is B. a horizontal row, and is numbered 1 through 7
hope this helps
Answer:
4.06 g BaCl₂
Explanation:
Molarity (M) is given by this formula:
We are given M and L in this equation; we can solve for moles of BaCl₂ and use stoichiometry to convert this amount to grams.
First convert 50.0 mL to L:
Plug this value for L and 0.390 for M into the equation.
Solve for mol by multiplying .05 to both sides.
We have .0195 mol BaCl₂. Now let's use stoichiometry to calculate the amount of grams in .0195 mol BaCl₂.
The molar mass of BaCl₂ is 208.23 g so by using stoichiometry...
There are 4.06 g of BaCl₂ in this solution.
The reaction produces fewer neutrons its <span>rate increases and it produces less energy.</span>