Question

Consider the following reaction, equilibrium concentrations, and equilibrium constant at a particular temperature. Determine the equilibrium pressure of H2. D2(g) + H2(g) ⇌ 2 HD(g) Kp = 1.80 P(D2)eq = 1.1 × 10-3 atm P(HD)eq = 2.7 × 10-3 atm

Answer 1

Answer:

1.4 * 10^-3

Explanation:

The equilibrium expression can be written as follows:

Keq = P [HD]^2/[ P[H2] * P[D2]]

Where P is pressure

1.80= (2.7 * 10^-3)^2 / ( 1.1 * 10^-3 * P[H2])

P[H2] = [2.7 * 10^-3]^2 / [1.8 * 1.1 * 10^-3]

P[H2] = 1.4 * 10^-3 atm