Answer: Mass
Explanation:
The moon and the Earth have a much higher gravitational pull than people because they weigh way more.
Answer:49.3
Explanation:4.1j/g c * 25g * (t2-45c)=455j
T2-45c = 455j/4.1j/g c * 25g
455/104.6
45+4.3= 49.3 celsius
Answer:
1943.1 moles
Explanation:
From the question given above, the following data were obtained:
Volume (V) = 50200 L
Temperature (T) = 25 °C
Pressure (P) = 720 mmHg
Number of mole (n) of H₂ =?
Next, we shall convert 25 °C to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
Temperature (T) = 25 °C
Temperature (T) = 25 °C + 273
Temperature (T) = 298 K
Next, we shall convert 720 mmHg to atm. This can be obtained as follow:
760 mmHg = 1 atm
Therefore,
720 mmHg = 720 mmHg × 1 atm / 760 mmHg
720 mmHg = 0.947 atm
Thus, 720 mmHg is equivalent to 0.947 atm
Finally, we shall determine number of mole of Hydrogen gas, H₂, needed to fill the balloon as follow:
Volume (V) = 50200 L
Temperature (T) = 298 K
Pressure (P) = 0.947 atm
Gas constant (R) = 0.0821 atm.L/Kmol
Number of mole (n) of H₂ =?
PV = nRT
0.947 × 50200 = n × 0.0821 × 298
47539.4 = n × 24.4658
Divide both side by 24.4658
n = 47539.4 / 24.4658
n = 1943.1 moles
Answer:
The denominator B = P1V1
Explanation:
We'll begin by writing the combine gas equation. This is shown below:
P1V1/T1 = P2V2/T2
Where:
P1 is the initial pressure.
V1 is the initial volume.
T1 is the initial temperature.
P2 is the final pressure.
V2 is the final volume.
T2 is the final temperature.
Now let us make T2 the subject of the formula to obtain our desired result. This is illustrated below:
P1V1/T1 = P2V2/T2
Cross multiply to express in linear form
P1V1T2 = P2V2T1
Divide both side by P1V1
T2 = P2V2T1/P1V1
From the above illustration,
The numerator A = P2V2T1
The denominator B = P1V1
If a solid piece of naphthalene is heated and remains at
80 degrees Celsius until it is completely melted, you know that 80 degrees Celsius
is the melting point of the solid naphthalene. This is the maximum temperature
at which the chromium is in its solid form.
