Answer:
The specific heat of the copper is 0.771 cal/ grams °C
Explanation:
Step 1: Data given
Mass of the piece of copper = 15.0 grams
The temperature of the wire changes from 12.0 °C to 79.0 °C
The amount of heat absorbed is 775 cal
Step 2: Calculate the specific heat of copper
Q = m*c*ΔT
⇒with Q = the heat absorbed = 775 cal
⇒with m = the mass of the copper = 15.0 grams
⇒with c = the specific heat of copper = TO BE DETERMINED
⇒with ΔT = The change in temperature = 79.0 °C - 12.0 °C = 67.0 °C
775 cal = 15.0 grams * c * 67.0 °C
c = 0.771 cal/gm °C
The specific heat of the copper is 0.771 cal/ grams °C
I don't see the options for an answer, so here is a list of all of the transition metals lol
- <em>Scandium</em>
- <em>Titanium</em>
- <em>Vanadium</em>
- <em>Chromium</em>
- <em>Manganese</em>
- <em>Iron</em>
- <em>Cobalt</em>
- <em>Nickel</em>
- <em>Copper</em>
- <em>Zinc</em>
- <em>Yttrium</em>
- <em>Zirconium</em>
- <em>Niobium</em>
- <em>Molybdenum</em>
- <em>Technetium</em>
- <em>Ruthenium</em>
- <em>Rhodium</em>
- <em>Palladium</em>
- <em>Silver</em>
- <em>Cadmium</em>
- <em>Lanthanum</em>
- <em>Hafnium</em>
- <em>Tantalum</em>
- <em>Tungsten</em>
- <em>Rhenium</em>
- <em>Osmium</em>
- <em>Iridium</em>
- <em>Platinum</em>
- <em>Gold</em>
- <em>Mercury</em>
- <em>Actinium</em>
- <em>Rutherfordium</em>
- <em>Dubnium</em>
- <em>Seaborgium</em>
- <em>Bohrium</em>
- <em>Hassium</em>
- <em>Meitnerium</em>
- <em>Darmstadtium</em>
- <em>Roentgenium</em>
- <em>Copernicium p</em>
this contains one significant figure
hope that helped
Yes this is know as the c value. It is usually used in q=mc change in temperature
