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Oliga [24]
3 years ago
8

Determine the number of roots, using the most efficient method possible.

Mathematics
1 answer:
Dmitry [639]3 years ago
7 0

Answer:

2 roots in every case, not all are real.

Step-by-step explanation:

All of these equations are quadratic equations (degree 2). Every quadratic has two roots. They may be identical (looks like 1 root), and they may be complex (zero real roots), but there are always 2 of them.

a) the y-value of the vertex is negative and the parabola opens downward (leading coefficient -5), so there are no real zeros and both roots are complex.

b) each binomial factor contributes a root. Both roots are real.

c) the discriminant is positive, (3²-4·2·1=1), so both roots are real.

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Alex787 [66]

<span>v(x)=(s/t)
= (3x - 6) / (-3x+6)
= [3(x-2)] / [-3(x-2)] --> 3 is factored out
= 1/-1 </span>---> common terms are cancelled out. 
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To find the domain, we equate the denominator to 0.
-3x+6 = 0
3x = 6
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Domain: all values except 2.

w(x)=(t/s)(x)
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= [-3x(x-2)] / [3(x-2)] --> 3 is factored out
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Solving for domain:
3x-6 = 0
3x = 6
x = 2
Domain: all values except 2.

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