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cupoosta [38]
3 years ago
10

What is the mass of a nitrogen dioxide molecule?

Chemistry
2 answers:
lakkis [162]3 years ago
8 0

The molar mass of nitrogen dioxide to the nearest gram-per-mole is 46 g/mol.

galina1969 [7]3 years ago
5 0
Answer: The molar mass of nitrogen dioxide to the nearest gram-per-mole is 46 g/mol.
Explanation: Nitrogen dioxide contains one nitrogen atom and two oxygen atoms.
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Which of the following is not the same as 2.97 milligrams a)0.0000297 kg b)0.00297 g or d)0.297cg
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0.0000297 kg would be the answer to ur question :)
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How many moles of iron can be recovered from 100.0 kg fe3o4?
Leokris [45]
Hello!

To know how many moles of iron can be recovered from 100 kg of Fe₃O₄ we'll need to use the molar mass of Fe₃O₄ and apply the conversion factor to go from kg of Fe₃O₄ to moles of Fe in the following way:

100 kg Fe_3O_4* \frac{1000 g}{1 kg}* \frac{1 mol Fe_3O_4}{231,533 g Fe_3O_4}* \frac{3 mol Fe}{1 mol Fe_3O_4}=1192,68 moles Fe

So, theoretically, one could recover 1192,68 moles of Fe from 100 kg of Fe₃O₄

Have a nice day!


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3 years ago
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emmasim [6.3K]

Other Causes of Extinction

In addition to habitat destruction, other human-caused problems are also threatening many species. These include issues associated with climate change, pollution, and over-population.

Habitat Destruction

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Humans often destroy the habitats of other organisms. Habitat destruction can cause the extinction of species.

Extinction is the complete disappearance of a species. Once a species is extinct, it can never recover.

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As we have learned earlier in the unit, invasive or non-native species can also change an ecosystem.

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6 0
2 years ago
One side of a plane wall is held at 200°C while the other side is exposed to a convective environment having T10°C and h 100 W/m
adelina 88 [10]

Answer:

\frac{\dot Q}{A} = 151.33 W/m^2

T_c = 25.153°C

Explanation:

Given data:

one side wall temperature 200°C

other side wall temperature 10°C

h = 100 W/m^2 °C

k = 2.6W/m °C

wall thickness L = 30 cm

we know that heat flux is given as

\frac{\dot Q}{A} = \frac{ T_A - T\infty}{\frac{L}{K} + \frac{1}{h}}

\frac{\dot Q}{A} = \frac{ 20- 10} {\frac{0.30}{2.6} + \frac{1}{100}}

\frac{\dot Q}{A} = 151.33 W/m^2

1515.33 W/m^2 = \frac{ T_A - T_c}{\frac{L}{K}}

solving for temperature for cold surface is given as

T_c = -1515.33 \times \frac{0.3}{2.6} + 200

T_c = 25.153°C

8 0
3 years ago
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