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madreJ [45]
3 years ago
12

CHECk out the illustration above. Using the correct terminology, matched with the correct lettered structures, explain how all a

re related to inheritance
Biology
2 answers:
andrew11 [14]3 years ago
8 0

Answer:

This is a cell (B) with a nucleus (C) containing DNA (A). The DNA is organized into chromosomes (D). A section of the chromosome that codes for a trait is called a gene (E).

Explanation:

blsea [12.9K]3 years ago
3 0

Answer:

what?if you add the "picture above" then i could help you.

Explanation:

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This squirrel lives in a forest and eats only acorns. <span>The squirrel will starve if it can't find enough food. </span>
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What do you call these 2 groups of ribs?
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In the first image, those are fake ribs that are attached to the sternum through  the costal cartilage

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The embryos of a fish, chicken and rabbit all contain a tail and pharyngeal pouches at some point during their early development
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Answer:

The answer is vertebrate.

Explanation:

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1. Flower position, stem length, and seed shape are three characters that Mendel studied. Each is controlled by an independently
maria [59]

Answer:

a. 1/64 AATTDD

b. 1/64 aattdd

c. 8/64=1/8 AaTtDd

d. 2/64 = 1/32 AATTDd or aattDd or AAttDd or aaTTDd

Explanation:

<u>Available data:</u>

  • Flower position: Axial (A) is dominant to Terminal (a)
  • Stem length: Tall (T) is dominant to dwarf (t)
  • Seed shape: Round (R) is dominant to wrinkled (r)

<u>Cross</u>:

Parental) AaTtDd   x   AaTtDd

Knowing that these four genes assort independently, then we can infer that the F1 will have the next genotypic proportions for each gene:

  • AA= 1/4

       Aa =2/4

       aa = 1/4

  • TT = 1/4

        Tt = 2/4

         tt = 1/4

  • DD = 1/4

        Dd = 2/4

        dd = 1/4

<em>This is the same as developing a Punnett square for each gene separately.</em>

Knowing this, to get each of the mentioned genotypes for each trait, we must multiply their respective genotypic proportions, like this:

a. homozygous for the three dominant traits, AATTDD

   AA1/4 x TT 1/4 x DD 1/4 = AATTDD 1/64

b. homozygous for the three recessive traits, aattdd

   aa 1/4 x tt 1/4 x dd 1/4 = aattdd 1/64

c. heterozygous for all three characters, AaTtDd

   Aa 2/4 x Tt 2/4 x Dd 2/4 = AaTtDd 8/16=1/8

d. homozygous for axial and tall, heterozygous for seed shape. There are four possibilities, all of them with the same result:

AATTDd --> 1/4  x 1/4 x 2/4 = 2/64=1/32

aattDd ---> 1/4 x 1/4 x 2/4 = 2/64=1/32

AAttDd ---> 1/4 x 1/4 x 2/4 = 2/64=1/32

aaTTDd ---> 1/4 x 1/4 x 2/4 = 2/64=1/32

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