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Alik [6]
3 years ago
13

Is 10/3 irrational or rational

Mathematics
1 answer:
Masteriza [31]3 years ago
7 0

It's rational


Rational numbers are numbers that you can put into the form of a/b.

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The next model of a sports car will cost 5.6% less than the current model. The current model costs $52,000. How much will the pr
Lostsunrise [7]

Answer:

49,088

Step-by-step explanation:

First you need to find 5.6% of 52,000. Simply multiply 52,000 by 0.056 (change the percent to a decimal) then you get 2,912.

Second, you need to subtract 2,912 from 52,000 which is 49,088

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3 years ago
There is a 5% sales tax on clothing at your favorite store you've gone shopping 4 times how much tax did you pay each time ?
salantis [7]
All you have to do is the amount she bought divided by 0.05 and then add the answer you get to the amount she bought each time
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3 years ago
HELP almost due in 5
skad [1K]

Answer:

A, D,F are triangle sides

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3 years ago
Find X if m/_ UVH=50°, m/_HVW=25x-5, and m/_ UVW = 35x-5.​
ra1l [238]

Step-by-step explanation:

first you have to solve for x

35x - 5=50

35-35x-5= 50-35

x-5=15

x- 5÷5=15÷5

x=3

Now we have to substitute x into the equation.

35×(3)-5=

175-5=170

angle UVW= 170

to find angle HUW instead of solving the equation just subtract 170 from 50 and you will get 120.

angle UVH=50

angle HUW=120

angle UVW=170

I hope this helps srry it took so long but gn and gl.

7 0
3 years ago
Factor the polynomial function over the complex numbers. f(x)=x^4-x^3-2x−4 Enter your answer in the box. f(x) = The answer is: (
Vladimir79 [104]

Answer:

Factors: (x+i\sqrt2)(x-i\sqrt2)(x+1)(x-2)=0

Step-by-step explanation:

We are given a polynomial:

f(x)=x^4-x^3-2x-4

We have to factor the given polynomial into its complex factors.

The factorization can be done as follows:

f(x)=x^4-x^3-2x-4 = 0\\x^4-x^3-2x-4 = 0\\x^4-4-x^3-2x=0\\\text{Identity: }a^2-b^2 = (a+b)(a-b)\\(x^4-4)-(x^3+2x) = 0\\(x^2+2)(x^2-2)-x(x^2+2) = 0\\(x^2+2)(x^2-2-x) = 0\\(x^2+2)(x^2-x-2) = 0\\(x^2+2)(x^2-2x-+x-2) = 0\\(x^2+2)((x(x-2)+1(x-2))=0\\(x^2+2)(x+1)(x-2)=0\\\text{Identity: }a^2-b^2 = (a+b)(a-b)\\(x^2-(\sqrt{-2})^2)(x+1)(x-2)=0\\(x+i\sqrt2)(x-i\sqrt2)(x+1)(x-2)=0

8 0
3 years ago
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