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Nutka1998 [239]
3 years ago
11

Which of these graphs do not represent constant rates of change? Check all that apply

Mathematics
1 answer:
sweet [91]3 years ago
4 0
The first and last graph
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HELP!!
Setler [38]
23.  If M' represents the complementary, then is the answer A.

24.  The answer is C.


4 0
3 years ago
Which of the following expressions is equivalent to −56−13?Select all that apply.
Dmitrij [34]
So -56 -13 = -69
So the answer would be 69?
You didn’t show the options.
5 0
3 years ago
Malcolm bought 6 bowls for $13.20. What is the unit rate
erica [24]
You divide the total amount by the umber of items. 13.20 divided by 6. This is 2.2. The unit rate is 2.2 dollars
5 0
3 years ago
Read 2 more answers
Please help me‼️‼️‼️
rewona [7]

Answer:

y= 4x-7

Step-by-step explanation:

First, we need to find the slope. We can do this by using the formula:

1) y₂-y₁/x₂-x₁

2) 9-5/5-3

3) 4/2

4) The slope is 2

Next, we have to first plug the slope (2) and one of the coordinate pairs (I chose (3,5)) into point-slope format.

5) y-y₁=m(x-x₁)

6) y-5 =4(x-3)

7) Now we just simplify this equation to make it slope intercept form (y=mx+b)

8) y-5= 4x-12

9) y=4x-7

And there you have it :)

6 0
2 years ago
Determine if the equation below is a function with independent variable x. If so, find the domain. If not, find a value of x to
Andre45 [30]

Answer:

No because it contains points (3,4) and (3,-4).  You cannot have a x assigned to more than one y-value if you want it to be a function.

Step-by-step explanation:

A function has one output per input.

If we are trying to determine if the given is a function of x, then x is the input.

However I can get two outputs from plugging in x=3.

3^2+y^2=25

9+y^2=25

Subtract 9 on both sides:

y^2=25-9

y^2=16

Take the square root of both sides:

y=\pm \sqrt{16}

y=\pm 4.

So input x=3 yields y=4 and y=-4.

Since this input has more than one output then the given is not a function of x.

----Also!

If you graph the equation, it is a circle with radius 5 and center (0,0). So I could I plug in any number for x between -5 and 5 excluding -5 and 5 which would yield only one output each. Since plugging in either one gives:

(\pm 5)^2+y^2=25

25+y^2=25

Subtract 25 on both sides:

y^2=25-25

Simplify:

y^2=0

There is only one value y such that when you square it gives you 0. That is 0.

x=5 only gives y=0 and x=-5 only gives y=0.

There is no circle, unless it is a circle with radius 0 which means it really wouldn't be a circle, that is a function.

8 0
3 years ago
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