The answer is 0.4%. The probability that a unit end in a rework can be calculated using the following equation:
P(rework)= P(defects found) * P(defect)
= .8 * .005
= .004
= 0.4%
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12.18 that is the answer to the question
Answer:
6
Step-by-step explanation:
18/9 = 2
2 * 3 = 6 presents