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Helga [31]
3 years ago
5

Multiply the polynomials.

Mathematics
1 answer:
dezoksy [38]3 years ago
7 0

48x^3-4x^2+18x-40 \text{ is the product of } (8x^2+6x+8)(6x-5)

<em><u>Solution:</u></em>

Given that we have to multiply the polynomials

(8x^2+6x+8)(6x-5)

Multiplying polynomials is similar to multiplying numbers

When you multiply two terms together you must multiply the coefficient (numbers) and add the exponents

Let us multiply the given polynomials

\rightarrow (8x^2+6x+8)(6x-5)

Multiply each term in first bracket with each term in second bracket

\rightarrow (8x^2)(6x) -5(8x^2)+6x(6x)+6x(-5)+8(6x)+8(-5)

Add the exponents and multiply the coefficients

\rightarrow 48x^3-40x^2+36x^2-30x+48x-40

Combine the like terms -30x and 48x

\rightarrow 48x^3-40x^2+36x^2+18x-40

Combine the like terms -40x^2 \text{ and } 36x^2

\rightarrow 48x^3-4x^2+18x-40

Thus the polynomials has been multiplied

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Answer:

B'(- 2, 2 )

Step-by-step explanation:

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This means add 3 to the original x- coordinate and subtract 2 from the original y- coordinate, that is

B(- 5, 4 ) → B'(- 5 + 3, 4 - 2 ) → B'(- 2, 2 )

8 0
2 years ago
Trina invited 60 people to her party and 42 said they would attend. What percent of people said they were NOT able to attend? Pl
Llana [10]
1. simplify 42/60 to 7/10 (42/60 divided by 2 is 21/30, 21/30 divided by 3 is 7/10)
2. if 10 x 10 = 100 than 7 x 10 = 70 so that would make it 70/100 which is 70%
so 70% is the answer

Hope this helps ;)
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5 0
3 years ago
Read 2 more answers
Differentiating a Logarithmic Function in Exercise, find the derivative of the function. See Examples 1, 2, 3, and 4.
Leni [432]

Answer:  \dfrac{2x^2-1}{x(x^2-1)}

Step-by-step explanation:

The given function : y=\ln(x(x^2 - 1)^{\frac{1}{2}})

\Rightarrow\ y=\ln x+\ln (x^2-1)^{\frac{1}{2}}    [\because \ln(ab)=\ln a +\ln b]

\Rightarrow y=\ln x+\dfrac{1}{2}\ln (x^2-1)}  [\because \ln(a)^n=n\ln a]

Now , Differentiate both sides  with respect to x , we will get

\dfrac{dy}{dx}=\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})\dfrac{d}{dx}(x^2-1) (By Chain rule)

[Note : \dfrac{d}{dx}(\ln x)=\dfrac{1}{x}]

\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})(2x-0)

[ \because \dfrac{d}{dx}(x^n)=nx^{n-1}]

=\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})(2x) = \dfrac{1}{x}+\dfrac{x}{x^2-1}\\\\\\=\dfrac{(x^2-1)+(x^2)}{x(x^2-1)}\\\\\\=\dfrac{2x^2-1}{x(x^2-1)}

Hence, the derivative of the given function is \dfrac{2x^2-1}{x(x^2-1)} .

8 0
3 years ago
Could someone please explain this problem to me?
disa [49]

Answer:

8/3

Step-by-step explanation:

Because all 4 angles are congruent, the sides are proportional.

the scale factor is 5/30 = 1/6.

meaning x = 16(1/6)=8/3.

7 0
1 year ago
What is5400300 in standard form
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