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kifflom [539]
3 years ago
15

Which example best represents the ability of carbohydrates to serve as structural components?

Biology
1 answer:
kaheart [24]3 years ago
3 0

Answer:

B, The rigid cell wall of green plants is composed of cellulose.

Explanation:

Cellulose is an organic compound, classified as a carbohydrate, that makes up a tough cell wall surrounding plant cells. It is a polysaccharide with beta 1, 4 d-glucose linkages (very strong bonds) making it very difficult to degrade by hydrolysis and enzymatic action. Through that, cellulose serves an important structural component because it provides roots and stems their rigidity, toughness and protection from microbial degradation.

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Which of the following is a node that you would expect to find on the cladogram for animals?
spayn [35]

Answer:

B - Deuterostome development

7 0
3 years ago
Read 2 more answers
What is the difference between genotype and phenotype
dlinn [17]

Answer:

  • person’s <u>genotype</u> is their unique sequence of DNA. More specifically, this term is used to refer to the two alleles a person has inherited for a particular gene. <u>Phenotype</u> is the detectable expression of this genotype – a patient’s clinical presentation.

Explanation:

person’s phenotype results from the interaction between their genotype and their environment.

The connection between genotype and phenotype is not always clear-cut. This means that you may encounter disparities between your patient’s genomic test result and their clinical presentation. Similarly, the phenotype of patients with a given genetic condition may vary greatly even within families.

6 0
1 year ago
Give two processes witch occur during interphase and witch are necessary for mitosis to take place
Degger [83]

DNA replication

Cell growth

4 0
3 years ago
The movement of glucose across the cell membrane through facilitated diffusion is a form of passive transport because
Artist 52 [7]

Answer:

The movement of glucose across the cell membrane through facilitated diffusion one of the form of passive transport because it does not require the energy to transport the glucose molecule across the cell membrane and the transport is along the concentration gradient.

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Through facilitated diffusion, some polar and charged molecules can cross the cell membrane without the expense of energy.

4 0
3 years ago
If you were to repeat the Meselson Stahl experiments, but rather than use N15 and N14, you use P32 and P31, how would the result
bonufazy [111]

Answer:

The correct answer will be option-C

Explanation:

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In the experiment, bacterial cultures were grown in the medium of 15N and 14N but if we repeat the experiment with P32 and P31 instead of 15N and 14N and centrifugation is performed then the banding pattern will be the same as of the previous experiment as the method of the replication is same that is semi-conservative.

Thus, Option-C is the correct answer.

4 0
3 years ago
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