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STatiana [176]
3 years ago
10

Drag each step and justification to the correct location on the table. Each step and justification can be used more than once, b

ut not all steps and justifications will be used.

Mathematics
1 answer:
Blizzard [7]3 years ago
8 0

Given equation :

2/3 y + 15 = 9.


We need to subtract 15 from both sides first.


<h3>2/3 y + 15-15 = 9 -15     <em>Subtraction property of equality.</em></h3>

Now, we need to simplify it.


We get


<h3>2/3 y  = - 6    <em> simplification </em></h3>

Now, we need to get rid 2/3 from left side.


On multiplying both sides by 3/2,


<h3>2/3 y * 3/2  = - 6  * 3/2  <em>Multiplication property of equality.</em></h3>

On simplifying, we get


<h3>y = -9    <em>simplification </em></h3>
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For the curve with equation y = <img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" align=
bixtya [17]

Answer:

Below.

Step-by-step explanation:

a) First we find the derivative of the function, which gives us the gradient in terms of x:-

y = x^2 + 4x + 3

Gradient at x = dy/dx = 2x + 4.

When the curve cuts the x-axis, y = 0:

x^2 + 4x + 3 = 0

(x + 1)(x + 3) = 0

so x = -1 and -3  where the curve cuts the x axis.

The gradients at these point are therefore:

At x = -1 gradient = 2(-1) + 4 = 2

at x = -3 gradient = 2(-3) + 4 = -2.

b) (i) Where the tangent is parallel to x axis the gradient = 0

so 2x + 4 = 0 giving x = -2.

We now need to substitute x = -2 into the original function to find the y coordinate.

So the coordinates are (-2, (-2)^2 + 4(-2) +3))

= (-2, -1)

(ii) First find the slope of the line 6x + 3y =  7:

3y = -6x + 7

y = -2x + 7/3.

So the slope is -2.

Thus -2 = 2x + 4

2x = -6

x = -3

So the coordinates are (-3, (-3)^2 + 4(-3) + 3)

= (-3, 0).

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3 years ago
The square root of 36y^3 =
Aleks04 [339]
The square roots of 36y^3 are plus and minus 6y^(3/2) .
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3 years ago
Soccer ball profit
Nady [450]

Answer:

$8.33 per soccer ball.

Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
Solve the system of equations:x + 3y - z = -4 2x - y + 2z = 13 3x - 2y - z = -9
tatiyna

Answer:

The solution to the system of equations is

\begin{gathered} x=\frac{179}{13} \\  \\ y=-\frac{279}{39} \\  \\ z=-\frac{48}{13} \end{gathered}

Explanation:

Giving the system of equations:

\begin{gathered} x+3y-z=-4\ldots\ldots\ldots\ldots\ldots\ldots..........\ldots\ldots\ldots\ldots.\ldots\text{.}\mathrm{}(1) \\ 2x-y+2z=13\ldots\ldots...\ldots\ldots\ldots\ldots..\ldots..\ldots\ldots\ldots\ldots\ldots.(2) \\ 3x-2y-z=-9\ldots\ldots\ldots.\ldots\ldots\ldots\ldots....\ldots\ldots.\ldots\ldots\ldots\text{.}\mathrm{}(3) \end{gathered}

To solve this, we need to first of all eliminate one variable from any two of the equations.

Subtracting (2) from twice of (1), we have:

5y-4z=-21\ldots\ldots\ldots\ldots\ldots.\ldots.\ldots..\ldots..\ldots\ldots.\ldots..\ldots\text{...}\mathrm{}(4)

Subtracting (3) from 3 times (1), we have

3y-5z=-3\ldots\ldots...\ldots\ldots..\ldots\ldots\ldots\ldots\ldots.\ldots\ldots\ldots\ldots\ldots..\ldots\ldots(5)

From (4) and (5), we can solve for y and z.

Subtract 5 times (5) from 3 times (4)

\begin{gathered} 13z=-48 \\  \\ z=-\frac{48}{13} \end{gathered}

Using the value of z obtained in (5), we have

\begin{gathered} 3y-5(-\frac{48}{13})=-3 \\  \\ 3y+\frac{240}{13}=-3 \\  \\ 3y=-3-\frac{240}{13} \\  \\ 3y=-\frac{279}{13} \\  \\ y=-\frac{279}{39} \end{gathered}

Using the values obtained for y and z in (1), we have

\begin{gathered} x+3(-\frac{279}{39})-(-\frac{48}{13})=-4 \\  \\ x-\frac{279}{13}+\frac{48}{13}=-4 \\  \\ x-\frac{231}{13}=-4 \\  \\ x=-4+\frac{231}{13} \\  \\ x=\frac{179}{13} \end{gathered}

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1 year ago
Plzz help e for brainliest if 2 people answer
Doss [256]

Answer:

B

Step-by-step explanation:

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3 years ago
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