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GaryK [48]
3 years ago
11

PLEASE HELP!!!!!!!!!!!!!

Chemistry
2 answers:
lions [1.4K]3 years ago
8 0

Answer:

Pd(O2C2H3)2

Explanation:

<u>Percentage composition of elements in the compound:</u>

Pd= 47.40%

O=28.50%

C=21.40%

H= 2.69%

<u>Molar mass of each element</u>

Pd= 106g/mol

O= 16g/mol

C= 12g/mol

H= 1g/mol

Step 1

Find the moles of each element in 100g sample using the formula

no. of moles(n)=mass/molar mass

<u>For Pd:</u> 47.40g/106g/mol

      n=   0.447 moles

<u>For O:</u> 28.50/16

      n= 1.78 moles

<u>For C:</u> 21.40/12

       n= 1.783 moles

<u>For H:</u> 2.69/1

     n= 2.69moles

Step 2

Now divide the no. of moles separately by the smallest number of moles. Smallest number of moles is <em>0.447</em>

Pd= 0.447/0.447

    = 1

O= 1.78/0.447

  = 3.9=4

C= 1.78/0.447

  = 3.9=4

H= 2.69/0.447

 = 6

Hence empirical formula is PdO4C4H6

The probable molecular formula is Pd(O_{2}C_{2}H_{3})2

Ghella [55]3 years ago
3 0

Answer:

Pd(O2CCH3)2

Explanation:

Below is an attachment containing the solution

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Answer: A. Gamma Ray

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4 0
3 years ago
Descreva as principais caracteristícas dos compostos ionicos
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a) They are solid at ambient temperatures of 25 ° C and pressure of 1 atm.

b) Ionic compounds represent high temperature melting and boiling.

 c) They are hard and brittle and then subjected to the impact, break easily, creating planar faces.

d) When dissolved in water, or pure liquid, carry electrical current due to the existence of ions that move freely and can be attracted by the electrodes, closing the electric circuit.

<span>e) His solvent is water. </span>

3 0
3 years ago
Consider 2 NOCl(g) \Longleftrightarrow⟺ 2 NO(g) + Cl2 (g) At 25oC under conditions other than equilibrium, there are 1.20 moles
nekit [7.7K]

Answer:

a) Q = 6.1875x10⁻³

b) The direction of the reaction is to form the products.

c) [Cl₂]e = 0.094 M

[NO]e =  0.190 M

[NOCl]e = 0.140 M

Explanation:

a) Q is the reaction quotient, and for a generic reaction aA + bB ⇄ cC + dD it is

Q = \frac{[C]^cx[D]^d}{[A]^ax[B]^b}

Which is the same equation for Kc, but in Kc expressions, the concentrations are in the equilibrium. Q is calculated at any time. So, for the reaction given

2NOCl(g) ⇄ 2NO(g) + Cl2(g)

Q = \frac{[Cl2]x[[NO]^2}{[NOCl]^2}

[Cl₂] = 0.220/5.00 = 0.044 M

[NO] = 0.450/5.00 = 0.090 M

[NOCl] = 1.20/5.00 = 0.240 M

Q = (0.044)x(0.090)²/(0.240)²

Q = 6.1875x10⁻³

b) Q < Kc, which means that there are fewer products to what are needed to the equilibrium. So the direction of the reaction is to form the products.

c)

2NOCl(g) ⇄ 2NO(g) + Cl2(g)

0.240           0.090      0.044         <em>Initial</em>

-2x                 +2x          +x             <em> Reacts</em> (stoichiometry is 2:2:1)

0.240-2x   0.090+2x   0.044+x    <em> Equilibrium</em>

Kc = \frac{(0.044+x)x(0.090+2x)^2}{(0.240 - 2x)^2}

1.86x10^{-1} = \frac{(0.044+x)*(8.1x10^{-3} +0.36x + 4x^2)}{(0.0576 - 0.96x +4x^2)}

3.564x10⁻⁴+0.01584x+0.176x²+8.1x10⁻³x+0.36x²+4x³ = 0.010714-0.17856x+0.744x²

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Solving this third grade equation in a computer program:

x = 0.05 M

So:

[Cl₂]e = 0.044 + 0.05 = 0.094 M

[NO]e = 0.090 + 2x0.05 = 0.190 M

[NOCl]e = 0.240 - 2x0.05 = 0.140 M

7 0
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Answer:

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Explanation:

final answer. C

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Varvara68 [4.7K]

Answer:

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Explanation:

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Cheers

4 0
3 years ago
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