Answer:
103.4 moles of hydrogen
Explanation:
Given data:
Moles of C₁₂H₂₂O₁₁ = 4.70 mol
Number of moles of hydrogen present = ?
Solution:
one mole of C₁₂H₂₂O₁₁ contain 22 moles of hydrogen. Thus in order to determine total number of moles in 4.70 moles of C₁₂H₂₂O₁₁ we will multiply the 22 moles of hydrogen with 4.70 moles of C₁₂H₂₂O₁₁.
1 mole of C₁₂H₂₂O₁₁ = 22 moles of Hydrogen
4.70 × 22 moles
103.4 moles of hydrogen
Answer:
⁹⁶₄₂Mo + ²₁H ⇒ ⁹⁸₄₃Tc
Explanation:
During the bombardment of a molybdenum target with deuterium ions, an element not found in nature was produced.The name of the element formed in the process is technetium. It is an element with the symbol Tc, mass number of 98, and atomic number 43. The nuclear equation is shown below:
⁹⁶₄₂Mo + ²₁H ⇒ ⁹⁸₄₃Tc
Technetium is the lightest element whose isotopes are all radioactive in nature except the fully ionized state of isotope ⁹⁷Tc. It is silvery gray in color and can be found between manganese and rhenium in group seven of the periodic table.
Answer:
You cannot make observations if you are 57 seconds late into the lab.
Explanation:
The atomic nucleus can split by decay into 2 or more particles as a result of the instability of its atomic nucleus due to the fact that radioactive elements possess an unstable atomic nucleus.
Now, the primary particles which are emitted by radioactive elements in order to make them decay are alpha, beta & gamma particles.
The half life equation is;
N_t = N₀(½)^(t/t_½)
Where:
t = duration of decay
t_½ = half-life
N₀ = number of radioactive atoms initially
N_t = number of radioactive atoms remaining after decay over time t
We are given;
t = 57 secs
N₀ = 100 g
Now, half life of Nitrogen-16 from online sources is 7.2 seconds. t_½ = 7.2
Thus;
N_t = 100(1/2)^(57/7.2)
N_t = 0.4139g
We are told that In order to make observations, you require at least .5g of material.
The value of N_t you got is less than 0.5g, therefore you cannot make observations if you are 57 seconds late.
Answer:
They apear this way because of refraction
Explanation:
Answer:
1:is option A as it have OH- group (base)
2:a),antacid as it's weak base
