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Vadim26 [7]
3 years ago
14

Which is the correct symbol for an isotope of iodine with 53 protons and 78 neutrons? es )))

Physics
1 answer:
Brut [27]3 years ago
8 0

 ¹³¹₅₃I

Explanation:

 Given data:

Number of protons = 53

Number of neutrons = 78

Unknown:

Symbol of the isotope:

 To symbolize any atom, we must know the chemical symbol of the atom.

From the given data, the number of protons in this atom will give us a good clue about this.

   Atomic number = number of protons = 53

The periodic table is based on the arrangement of elements using their atomic numbers.

  Iodine is the element with an atomic number of 53

 Mass number = number of protons + number of neutrons = 53 + 78 = 131

The symbol of the isotope is              ¹³¹₅₃I

learn more:

Atomic number brainly.com/question/2057656

#learnwithBrainly

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A butcher grinds 5 and 3/4 lb of meat then sells it for 2 and 2/3 pounds to the customer what is the maximum amount me that the
KiRa [710]

Answer:

The maximum amount of meat that the butcher can sell is  3\frac{1}{12}\:lb

Explanation:

The maximum amount can be found by taking the difference of mixed numbers.

5\frac{3}{4}-2\frac{2}{3}\\\\\mathrm{Subtract\:the\:numbers:}\:5-2=3\\\\\mathrm{Combine\:fractions:\:}\frac{3}{4}-\frac{2}{3}=\frac{1}{12}\\\\=3\frac{1}{12}\\

Best Regards!

8 0
3 years ago
You want to place a mirror at a blind turn on the staircase in your house. Which would be best suited for this purpose?
Eduardwww [97]
You can't see beyond a blind turn, so a mirror would allow you to see around the corner.
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8 0
3 years ago
Assertion(A):The distance moved by an object in unit time is called its speed. Reason (R):Faster vehicles have higher speeds. i)
ikadub [295]

Answer:

it's ii) R is correct while A is incorrect

Explanation:

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8 0
3 years ago
Mars has two moons, Phobos and Deimos. Phobos orbits Mars at a distance of 9380 km from Mars's center, while Deimos orbits at 23
Sloan [31]

Answer:

The ratio is   \frac{T_1}{T_2}  = 3.965

Explanation:

From the question we are told that

   The  radius of Phobos orbit is  R_2 =  9380 km

    The radius  of Deimos orbit is  R_1  =  23500 \  km

Generally from Kepler's third law

    T^2 =  \frac{ 4 *  \pi^2 *  R^3}{G * M  }

Here M is the mass of Mars which is constant

        G is the gravitational  constant

So we see that \frac{ 4 *  \pi^2  }{G * M  } =  constant

   

    T^2 = R^3   *  constant      

=>  [\frac{T_1}{T_2} ]^2 =  [\frac{R_1}{R_2} ]^3

Here T_1 is the period of Deimos

and  T_1 is the period of  Phobos

So

      [\frac{T_1}{T_2} ] =  [\frac{R_1}{R_2} ]^{\frac{3}{2}}

=>    \frac{T_1}{T_2}  =  [\frac{23500 }{9380} ]^{\frac{3}{2}}]

=>    \frac{T_1}{T_2}  = 3.965

   

8 0
3 years ago
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