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Grace [21]
3 years ago
7

VR of a single movable Pulley is 2,why?​

Physics
1 answer:
IRISSAK [1]3 years ago
5 0

Explanation:

Hey, there!!

Single movable pulley has 2 VR because in single fixed pulley, load is supported with two segments of the string. It makes the effort distance double of the load distance. {As VR = No.of pulley used or number of rope segments that supports the load.}

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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mario62 [17]

Using

V = Amplitude x angular frequency(omega)

But omega= 2πf

= 2πx875

=5498.5rad/s

So v= 1.25mm x 5498.5

= 6.82m/s

B. .Acceleration is omega² x radius= 104ms²

5 0
3 years ago
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Proved that<br>V = u+at<br>​
kondaur [170]

Answer:

\sf Proof \ below

Explanation:

We know that acceleration is change in velocity over time.

\sf a=\frac{\triangle v}{t}

\sf a=\frac{v-u}{t}

v is the final velocity and u is the initial velocity.

Solve for v.

Multiply both sides by t.

\sf at=v-u

Add u to both sides.

\sf at + u=v

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3 years ago
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A person pushes a 125 kg object initially at rest on a frictionless surface. The object ends up with a final velocity of 1.40 m/
mr Goodwill [35]

Answer:

a person pushes a 125 kg

Explanation:

8 0
2 years ago
Two boys are sliding toward each other on a frictionless, ice-covered parking lot. Jacob, mass 45 kg, is gliding to the right at
Maurinko [17]

Answer:

v=0.3381\ m.s^{-1} in the direction of motion of Jacob

Explanation:

Given:

mass  of Jacob, m_j=45\ kg

velocity of Jacob, v_j=8.08\ m.s^{-1}

mass of Ethan, m_e=31\ kg

velocity of Ethan, v_e=10.9\ m.s^{-1}

Now using the conservation of linear momentum for the case:

(When the two masses in motion combine to form one after the collision then they will move together in the direction of the greater momentum.)

(m_j+m_e).v=m_j.v_j-m_e.v_e

(45+31)\times v=45\times 8.08-31\times 10.9

v=0.3381\ m.s^{-1} in the direction of motion of Jacob as it was assumed to be positive.

5 0
3 years ago
A go-kart and rider have a mass of 14 kg. If the cart accelerates at 6 m/s² during a 40 m sprint in 100 seconds, how much power
Nutka1998 [239]

Answer:

<em>P=33.6 \ W</em>

Explanation:

<u>Mechanical Work and Power</u>

Work is the amount of energy transferred by a force. It's a scalar quantity, with SI units of joules.

Being \vec F the force vector and \vec s the displacement vector, the work is calculated as:

W=\vec F\cdot \vec s

If both the force and displacement are parallel, then we can use the equivalent scalar formula:

W=F.s

Mechanical Power is the amount of energy transferred or converted per unit of time. The SI unit of power is the watt, equal to one joule per second.

The power can be calculated as:

\displaystyle P=\frac {W}{t}

Where W is the work and t is the time.

If an object of mass m has an acceleration a, the net force is:

F=m.a

The go-kart and rider have a mass of m=14 kg and accelerate at 6 m/s^2, thus the net force applied is:

F=14\cdot 6 = 84\ N

The work done by the cart when traveling d= 40 m is:

W=84\cdot 40

W=3,360\ J

Finally, the power for t= 100 seconds is:

\displaystyle P=\frac {3,360}{100}

P=33.6 \ W

5 0
3 years ago
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