Question

A gas occupies a volume of 1.00 L at 25.0°C. What volume will the gas occupy at 1.00 x10^2 °C?

Answer 1

Answer : The volume of gas occupy at $1.00\times 10^2^oC$ is, 1.25 L

Explanation :

Charles' Law : It states that volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

Mathematically,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

where,

$V_1\text{ and }T_1$ are the initial volume and temperature of the gas.

$V_2\text{ and }T_2$ are the final volume and temperature of the gas.

We are given:

$V_1=1.00L\\T_1=25.0^oC=(25.0+273)K=298K\\V_2=?\\T_2=1.00\times 10^2^oC=((1.00\times 10^2)+273)K=373K$

Putting values in above equation, we get:

$\frac{1.00L}{298K}=\frac{V_2}{373K}\\\\V_2=1.25L$

Therefore, the volume of gas occupy at $1.00\times 10^2^oC$ is, 1.25 L