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Rama09 [41]
3 years ago
12

1.) Consider the processes or reactions, indicate which side of the reaction will have the greatest entropy AND explain why. (4

pts) a. CO2 (s)CO2 (g) b. CaCO3 (s)-) Cao (s) + CO2 (g) c. 2 NO2 (g) -> N204 (g) d. H20 (1) at 25 °C heated to 52 °C
Chemistry
1 answer:
ratelena [41]3 years ago
6 0

Answer:

A. Right side since CO2 has has more entropy than solid CO2

B. Right side since gaseous CO2 is present on right side

C. Left side since more no of gaseous molecules om left side

D. Right side since on heating of water at 52C starts boiling hence more entropy for vapour.

Explanation:

Generally entropy is the measurement of randomness and follows the order gas>liquid>solid

You might be interested in
Complete the dissociation reaction and the corresponding Ka equilibrium expression for each of the following acids in water. (Ty
anastassius [24]

Answer :

(A) The dissociation reaction of HC_2H_3O_2 will be:

HC_2H_3O_2(aq)\rightleftharpoons H^+(aq)+C_2H_3O_2^-(aq)

The equilibrium expression :

K_a=\frac{[H^+][C_2H_3O_2^-]}{[HC_2H_3O_2]}

(B) The dissociation reaction of Co(H_2O)_6^{3+} will be:

Co(H_2O)_6^{3+}(aq)\rightleftharpoons H^+(aq)+Co(H_2O)_5(OH)^{2+}(aq)

The equilibrium expression :

K_a=\frac{[H^+][Co(H_2O)_5(OH)^{2+}]}{[Co(H_2O)_6^{3+}]}

(C) The dissociation reaction of CH_3NH_3^+ will be:

CH_3NH_3^+(aq)\rightleftharpoons H^+(aq)+CH_3NH_2(aq)

The equilibrium expression :

K_a=\frac{[H^+][CH_3NH_2]}{[CH_3NH_3^+]}

Explanation :

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.

As we know that the concentrations of pure solids and liquids are constant that is they do not change. Thus, they are not included in the equilibrium expression.

(A) The dissociation reaction of HC_2H_3O_2 will be:

HC_2H_3O_2(aq)\rightleftharpoons H^+(aq)+C_2H_3O_2^-(aq)

The equilibrium expression of HC_2H_3O_2 will be:

K_a=\frac{[H^+][C_2H_3O_2^-]}{[HC_2H_3O_2]}

(B) The dissociation reaction of Co(H_2O)_6^{3+} will be:

Co(H_2O)_6^{3+}(aq)\rightleftharpoons H^+(aq)+Co(H_2O)_5(OH)^{2+}(aq)

The equilibrium expression of Co(H_2O)_6^{3+} will be:

K_a=\frac{[H^+][Co(H_2O)_5(OH)^{2+}]}{[Co(H_2O)_6^{3+}]}

(C) The dissociation reaction of CH_3NH_3^+ will be:

CH_3NH_3^+(aq)\rightleftharpoons H^+(aq)+CH_3NH_2(aq)

The equilibrium expression of CH_3NH_3^+ will be:

K_a=\frac{[H^+][CH_3NH_2]}{[CH_3NH_3^+]}

3 0
3 years ago
GOOD REWARD<br> I will report those who gives random answers.
Helen [10]

Answer:

3 mol AlCl₃.

Explanation:

Hello!

In this case, according to the specified reactants and products, it is possible to set up the following balanced chemical reaction:

Al(NO_3)_3+3NaCl\rightarrow 3NaNO_3+AlCl_3

Whereas we evidence the 1:3 mole ratio between aluminum nitrate and sodium chloride; thus, since different moles were reacting, we need to identify the limiting reactant by computing the moles of AlCl₃ produced by each reactant as follows:

n_{AlCl_3}^{by\ Al(NO_3)_3}=4molAl(NO_3)_3*\frac{1molAlCl_3}{1molAl(NO_3)_3} =4molAlCl_3\\\\n_{AlCl_3}^{by\ NaCl}=9molNaCl*\frac{1molAlCl_3}{3molNaCl} =3molAlCl_3

Thus, we infer that NaCl is the limiting reactant as it produces the fewest moles of AlCl₃; consequently the produced amount of this product is 3 mol.

Best regards!

5 0
3 years ago
Select the correct set of quantum numbers (n, l, ml, ms) for the first electron removed in the formation of a cation for stronti
matrenka [14]

Answer:

5,0,0,-1/2

Explanation:

The quantum numbers are a way to characterize the electrons, and so, identify the region that it's more probable to find it (orbital). They are:

- Principal quantum number (n): represents the shell or level, and varies from 1 to 7, and are represented by the letter K, L, M, N, O, P, and Q.

- Azimuthal quantum number (l): represents the subshell or sublevel, and is represented by 0,1,2,3.., and for the letters s, p, d, f,...

- Magnetic quantum number (ml): represents the orbital. It varies from -l to +l passing by 0. Each orbital can have 2 electrons.

- Spin quantum number (ms): represents the spin of the electron. It can be +1/2 or -1/2.

The strontium has an atomic number equal to 38, by the Linus Pauling's diagram, the electronic distribution is:

1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²

The valence electron is at the subshell 5s, which has only one magnetic quantum number: 0. Because it has 2 electrons, the first one has spin =1/2, and the other -1/2. So the first electron of the formation of cation has quantum numbers:

n = 5; l = 0; ml = 0; ms = -1/2

7 0
3 years ago
If we mix 25 grams of sodium bromide with a large amount of potassium chloride, what will our theoretical yield of sodium chlori
erik [133]

Answer:

Theoretical yield of sodium chloride = 14.04 g

Explanation:

Given data:

Mass of sodium bromide = 25 g

Theoretical yield of sodium chloride = ?

Solution:

Chemical equation:

NaBr + KCl  → NaCl  + KBr

Number of moles sodium bromide:

Number of moles = Mass /molar mass

Number of moles = 25.0 g / 102.9 g/mol

Number of moles = 0.24 mol

Now we will compare the moles of NaCl with NaBr  .

                  NaBr         :               NaCl

                    1               :               1

                 0.24           :            0.24

Theoretical yield of sodium chloride:            

Mass  = moles × molar mass

Mass = 0.24 mol ×  58.5 g/mol

Mass =  14.04 g

7 0
3 years ago
What are the different phases of matter and their characteristics?
Novay_Z [31]

Answer:

The five phases of matter. There are four natural states of matter: Solids, liquids, gases and plasma. The fifth state is the man-made Bose-Einstein condensates. In a solid, particles are packed tightly together so they don't move much.

3 0
3 years ago
Read 2 more answers
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