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Shalnov [3]
3 years ago
13

If you need to reverse the following reaction and multiply it by 2 in order for it to be an intermediate reaction in a Hess's la

w problem, what would be the final value for the enthalpy of reaction you use for this intermediate reaction? H2 + 0.5 O2 H2O, H = -286 kJ
Chemistry
1 answer:
jekas [21]3 years ago
4 0
We have that the total enthalpy of the reaction changes with the quantity of the reactants and it is proportional to them. Also, the reverse of a reaction has the opposite enthalpy. Hence, since we need to multiply by 2, the reactants are double and thus the value of the enthalpy is 2 as big. Also, since we are using the inverse reaction, we must also invert the sign. Thus, for this reaction we must use the value H=572 kJ.
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If you need to extract a 50 ml aqueous solution with 50 ml of dichloromethane, what is the minimum size of a separatory funnel y
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The dichloromethane (DCM) has less density than water and also the polarity of water is much more than DCM. So the mixture of water and dichloromethane will always be a heterogeneous mixture. In the mixture dichloromethane will be always up of the water layer. The volume of the separatory funnel which contains the mixture of DCM and water must have to be more than the total volume of the liquids thus the volume of the funnel will be more than (50+50) = 100mL.

The caution have to consider during the separation are-

1. The separatory funnel have to shake well with lid and have to settle down for some times until the two liquid separated.

2. The lid should be open very slowly as the vapor pressure of DCM is more and it will float on the water.

3. After this the stopcock should be opened and slowly the water will come out first followed by DCM.      

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3 years ago
Write the net chemical equation for the production of nitric acid from nitrogen, hydrogen and oxygen. be sure your equation is b
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Is potassium a compound?​
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A student asks why the ashes from a fire have a much lower mass than wood that was burned.
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6 0
3 years ago
Carlos is making phosphorus trichloride using the equation below. He uses 15.5 g of phosphorus and collects 50.9 g of phosphorus
alex41 [277]

Answer: 35.4 g

Explanation:

The balanced reaction is :

2P+3Cl_2\rightarrow 2PCl_3

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of phosphorous}=\frac{15.5g}{31g/mol}=0.50moles

\text{Moles of phosphorous chloride}=\frac{50.9g}{137g/mol}=0.372moles

2P+3Cl_2\rightarrow 2PCl_3

According to stoichiometry :

2 moles of phosphorous chloride are produced by = 3 moles of Cl_2

Thus 0.37 moles of phosphorous chloride are produced by=\frac{3}{2}\times 0.372=0.558moles of Cl_2

Mass of Cl_2=moles\times {\text {Molar mass}}=0.558moles\times 71g/mol=35.4g

Thus 35.4 g of chlorine reacted with the phosphorus

5 0
3 years ago
Read 2 more answers
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