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3 years ago

Need answer ASAP!!!!!!

Mathematics

2 answers:

Alona [7]3 years ago

6 0

I think the Answer is 38.88π Hope I helped!

algol133 years ago

4 0

I believe the answer is 1.44, hope I helped! Sorry if I didn't!

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A juice manufacturing company designed a carton as shown below. What is the name of the three-dimensional

kodGreya [7K]

Answer: rectangular prism and a pyramid I think

Step-by-step explanation:

7 0

3 years ago

you draw a card from a deck if you get a red card you win nothing if you get a spade you win 14 for any club you win 28 plus an

Readme [11.4K]

Answer: Standard deviation is 11.6

Step-by-step explanation:

Sample mean 52/4=13

X. X---x(bar). X---x(bar)^2

0. 0--13=-13. -13^2=169

14. 14--13=1. 1^2=1

28. 28--13=15. 15^2=225

10. 10--13=--3. --3^2=9

__________________________

52. 404

Standard deviation=√404/3=11.6

6 0

3 years ago

A batch of 40 parts contains six defects. If two parts are drawn randomly one at a time without replacement, what is the probabi

adell [148]

Answer:

a) Therefore, the probability is P=1/52.

b) Therefore, the probability is P=9/400.

Step-by-step explanation:

We know that a batch of 40 parts contains six defects.

a) We calculate the probability that the both parts are defective, if two parts are drawn randomly one at a time without replacement.

The probability for the first is 6/40.

The probability for the second is 5/39.

We get:

$P=\frac{6}{40}\cdot \frac{5}{39}\\\\P=\frac{1}{52}$

Therefore, the probability is P=1/52.

b) We calculate the probability that the both parts are defective, if two parts are drawn randomly one at a time with replacement.

The probability for the first is 6/40.

The probability for the second is 6/40.

We get:

$P=\frac{6}{40}\cdot \frac{6}{40}\\\\P=\frac{9}{400}$

Therefore, the probability is P=9/400.

6 0

3 years ago

Part A: Find the LCM of 7 and 12. Show your work. (3 points)

inna [77]

Answer:

A. 84; B. 8; C. 8 × 19

Step-by-step explanation:

Part A. Least common multiple

Step 1. List the prime factors of each.

7 = 7

12 = 2 × 2 × 3

Step 2: Multiply each factor the greatest number of times it occurs in either number.

7 has one 7; 12 has two 2s and one 3.

LCM = 7 × 2 × 2 × 3

LCM = 7 × 12

LCM = 84

Part B. Highest common factor

Find all the factors of 56 and 96.

Factors of 56: 1, 2, 4, 7, 8, 14, 28

Factors of 96: 1, 2, 4, 6, 8, 12, 16, 24, 32, 48

The highest factor that in both 56 and 96 is 8.

Part C. Factoring

56 + 96 = 8(7 + 12) = 8 × 19

The GCF is 8.

19 = 7 + 12 is the sum of two numbers that do not have a common factor.

4 0

4 years ago

Identify the rule that could possibly describe this set of data.

Harlamova29_29 [7]

The answer is a

(ignore this i don’t have enough characters)

3 0

3 years ago

Read 2 more answers