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3 years ago

Identify the start and stop codons in the mrna sequence 5'-uauccauggcacuuuaaac-3'. what is the resulting amino acid sequence

Biology

2 answers:

Colt1911 [192]3 years ago

3 0

Answer;

-Start codon: AUG;

-Stop codon: UAA;

-Amino acid sequence: Met-Ala-Leu-stop

Explanation;

-A codon is a sequence of three DNA or RNA nucleotides that corresponds with a specific amino acid.

-The start codon marks the site at which translation into protein sequence begins, and the stop codon marks the site at which translation ends. The start codon is often preceded by a 5' untranslated region (5' UTR). AUG is the most common start codon. There are three RNA stop codons: UAG, UAA, and UGA.

Vedmedyk [2.9K]3 years ago

3 0

It is on the genetic code that the biosynthesis of proteins rests. The DNA is transcribed into messenger RNA (mRNA). This is translated by the ribosomes that assemble the amino acids present on transfer RNAs (tRNAs).

The right answers are:

Start codon: 5'-uauccauggcacuuuaaac-3'. It codes for Methionine

Stop codon: 5'-uauccauggcacuuuaaac-3'

We will have three amino acids produced (each one has a codon of three nucleotides): 5'-uauccauggcacuuuaaac-3'.
Stop codon does not code for an aminoacid.

The AA sequence is Methionine-Alanine-Leucine.

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