Answer:
1.77 * 10^-3
Explanation:
From the titration formula;
Let
CA = concentration of acid
CB = concentration of base
VA = volume of acid
VB = volume of base
NA = number of moles of acid
NB = number of moles of base
The equation of the reaction is;
M(OH)2(aq) + 2HCl(aq) -------> MCl2(aq) + 2H2O(l)
So;
CAVA/CBVB= NA/NB
CAVANB = CBVBNA
CB= CAVANB/VBNA
CB= 0.173 * 25.10 * 1/28.5 * 2
CB= 4.3423/57
CB= 0.0762 M
This implies that the solubility of M(OH)2 = 0.0762 M
M(OH)2(s) ----> M^+(aq) + 2OH^-(aq)
So
Ksp = x * (2x)^2
Ksp = 4x^3
x = 0.0762
Ksp= 4(0.0762)^3
Ksp = 1.77 * 10^-3
The answer is C) Communities in an effort to beautify local neighborhoods
Here we have to get the amount of heat will generate by 510.0 kg of sodium sulfate decahydrate at night assuming complete reaction and 100% efficiency of heat transfer.
510.0 kg of sodium sulfate decahydrate will produce 5.603 × 10⁵ kJ of heat energy.
The molecular weight of sodium sulfate decahydrate (H₂₀Na₂O₁₄S) 322.186 g/mol.
Thus 510.0 kg of H₂₀Na₂O₁₄S is equivalent to
= 1582.936 mol of H₂₀Na₂O₁₄S.
Now per mole of H₂₀Na₂O₁₄S will transfer 354 kJ heat.
Thus 1582.936 mol will transfer 1582.936 × 354 kJ = 5.603×10⁵ kJ of heat.
Henceforth, 510.0 kg of sodium sulfate decahydrate will produce 5.603 × 10⁵ kJ of heat energy.
There is some missing information.