Answer:
Percent error = 20%
Explanation:
The percent error is calculated using the following equation:
Percent error = |(approximate value - exact value)| / (exact value) x 100%
In this problem, the approximate value was 184 mL and the exact value was 230.0 mL
Percent error = |(184 mL - 230.0 mL)| / (230.0 mL) x 100% = 20%
Answer:
no the answer is oxidation
Answer:
The heat of combustion of magnesium metal is 24.76 kJ/gram
Explanation:
Step 1: Data given
Mass of magnesium sample = 0.1946 grams
Molar mass of magnesium = 24.3 g/mol
bomb calorimeter that has a heat capacity of 1349 J/°C
Mass of water = 500 grams
Temperature change = 1.40 °C
Step 2: Calculated heat released
Q = (1349 J/°C * 1.40 °C) + (500 grams * 4.184 J/g°C * 1.40 °C)
Q =4817.4 J = 4.82 kJ
Step 3: Calculate the heat given off by the burning Mg, in kJ/g
4817.4 J / 0.1946 grams = 24755.4 J/ gram = 24.76 kJ/ gram
The heat of combustion of magnesium metal is 24.76 kJ/gram
Answer: the answer is d
Explanation: i took the test
