3. The picture below is an example of a _________ _________. (Answer is 2 words)
1 answer:
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Answer:
The change in enthaply when 10.0 g of nitrogen triiodide decomposes is -3.67 kJ.
Explanation:
Enthalpy of the reaction when 2 moles of nitrogen triiodide decomposed =
Enthalpy of the reaction when 1 moles of nitrogen triiodide decomposed :
Mass of nitrogen triiodide decomposed = 10.0 g
Moles of nitrogen triiodide =
Change in enthaply when 0.02532 moles of nitrogen triiodide decomposed:
Answer:
8.4) 27.1 cm³
8.5) 0.217 mol/dm³
Explanation:
Please see attached picture for full solution.
8.4) Since the results from titrations 3-5 are within 0.10cm³ from each other, these 3 results are concordant.
8.5) Find mol of sulfuric acid to find mol of NaOH using mole ratio. Equation has already been balanced for you, so mole ratio of NaOH to H2S04 is 2:1. To find concentration of NaOH, divide the number of moles by the volume in dm³ since the units for concentration is mol/dm³, which you can think of as the number of moles of NaOH in a dm³ of solution.
1 dm³ = 1000cm³
Thus, 1cm³= 1/1000 dm³
