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harkovskaia [24]
3 years ago
6

Look up and compare the normal boiling points and normal melting points of H2O and H2S. Based on these physical properties, whic

h substance has stronger intermolecular forces? What kinds of intermolecular forces exist for each molecule?
Chemistry
1 answer:
NeTakaya3 years ago
7 0

Explanation:

Both melting and boiling point of water are much higher that that of H2S.

The MP and BP of water are 0°C and 100°C respectively whereas the MP and BP of H2S are -82°C and -60°C respectively.

Clearly, the intermolecular forces in H2O are much stronger than in H2S because, H2O has hydrogen bonding in it, which is both inter and intra. Whereas H2S has only weak van der waal force between their molecules. This is why boiling and melting points of H2O is more than that of H2S.

Hydrogen bonding is a particular type of dipole-dipole association which occurs between atoms of hydrogen bound to strongly electronegative atoms that are either fluorine, oxygen or nitrogen.

The hydrogen atom's partially positive side is drawn to the partially negative end of these atoms found in some other molecule. It is a strong binding mechanism between the molecules.

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when hydrogen atom absorbs a photon, and an electron moves level 1 to level 2, what happens to the energy of the atom?
pychu [463]

Answer:

When an electron is hit by a photon of light, it absorbs the quanta of energy the photon was carrying and moves to a higher energy state. One way of thinking about this higher energy state is to imagine that the electron is now moving faster, (it has just been "hit" by a rapidly moving photon).

Explanation: pls mark brainliest :))

7 0
3 years ago
When steam from a pan of boiling water reaches a cool window, it condenses. How much
andriy [413]

Because the air right above your hot pan of water is so warm, the water vapor can be quickly absorbed there. When the heat is removed, the hot convective up current from the pan vanishes and is replaced with cooler air that can no longer contain as much moisture, which makes the condensing water vapour visible.

First, it's important to discuss the "steam" that is produced by the hot water. While we refer to it as steam, it is not. Water that is heated above 100 degrees Celsius produces steam. The only area in the kitchen where you can see it clearly is if you look very closely at the spout of a boiling kettle. The first 5mm (1/4") of the liquid will be clear when it is boiling very near to the spout.

Learn more about Steam here-

brainly.com/question/15447025

#SPJ4

3 0
1 year ago
N2H4 + N2O4 --> N2 + H2O
ahrayia [7]

Answer:

  1. The limiting reagent is N2O4
  2. 14,09g

Explanation:

  • First, we adjust the reaction.

2N_{2} H_{4} + N_{2} O_{4} ⇄6N_{2} +  4H_{2}O

  • Second, we assume that the participating moles are equal to the stoichiometric ratios because we do not know the amounts of the reagents.

We can determinate what is the limiting reagent comparing of product amounts which can be formed from each reactant.

Using N_{2} H_{4} to form H_{2}O

               molH_{2} O = 1mol N_{2} H_{4} } . \frac{4 mol H_{2} O}{2mol N_{2} H_{4} }. \frac{18\frac{g}{mol}  H_{2} O}{1mol H_{2} O_} } . \frac{ 1 mol N_{2}H_{4}  }{32,04\frac{g}{mol}  N_{2} H_{4} }

                                           molH_{2} O = 1, 125 mol

Using N_{2} O_{4} to form H_{2} O

              molH_{2} O = 1mol N_{2} O_{4} } . \frac{4 mol H_{2} O}{1mol N_{2} O_{4} }. \frac{18\frac{g}{mol}  H_{2} O}{1mol H_{2} O_} } . \frac{ 1 mol N_{2}O_{4}  }{92\frac{g}{mol}  N_{2} O_{4} }

                                           molH_{2} O = 0,783 mol

The limiting reagent is N2O4, because can produce only 0, 783 mol of H2O.

This is the minimum measure can be formed of each product.

∴                          MassOfH_{2}O = 0,783mol . 18\frac{g}{mol}

                                      MassOfH_{2}O = 14,09g

5 0
4 years ago
Which molecule contains a nonpolar covalent bond
irakobra [83]
Atom or a part of chemistry
6 0
3 years ago
a cylinder with a movable piston contains 250 cm3 air at 10°C. if the pressure is kept constant, at what temperature would you e
soldi70 [24.7K]

Answer:

T₂ = 169.89 K

Explanation:

Given data:

Initial volume = 250 cm³

Initial temperature = 10°C (10+273.15 K = 283.15 K)

Final temperature = ?

Final volume = 150 cm³

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

T₂ = T₁V₂/V₁  

T₂ = 283.15 K × 150 cm³ /  250 cm³

T₂ = 42472.5 K. cm³  / 250 cm³

T₂ = 169.89 K

5 0
3 years ago
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