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4 years ago

How many logs does Teresa need to maintain the fire for 18 hours

Mathematics

2 answers:

murzikaleks [220]4 years ago

7 0

Answer:

27 logs for 18 hours

pishuonlain [190]4 years ago

5 0

I'm pretty sure it's 27 logs

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K · (3.2 ÷ 4) = 1.6<br><br> k =

SVEN [57.7K]

K=2. You have to divide 3.2 by 4, then divide both sides by 0.8, finally, you have your answer, K=2.

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3 years ago

Which of the following are quadratic equations

Igoryamba

Answer:

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3 years ago

Which graph represents the function y= 2/3x-2?<br>

Volgvan

I believe it’s the 3rd one

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3 years ago

Read 2 more answers

Please help I need this answer

kakasveta [241]

Answer:

This is your answer

Step-by-step explanation:

(For the second step I multiplied 6 and 4)

3 0

3 years ago

This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an

stealth61 [152]

Answer:

$M_x = 2, M_y = 3$

Center of mass at $(\frac{3}{10},\frac{2}{10})$

Step-by-step explanation:

Given a set of objects $m_1, \dots, m_k$ located at the points $P_1(x_1, y_1), \dots, P_k(x_k,y_k)$ The moments Mx and My are calculated as follows.

$M_x = \sum_{n=1}^k m_n\cdot y_n, M_y = \sum_{n=1}^k m_n\cdot x_n$

and the Center of mass is given at the coordinates $(\frac{My}{M}, \frac{Mx}{M})$ where M is the total mass of the system.

We have that m1=3, m2=4 and m3=3, so M = 3+4+3 = 10.

We have that m1 is at point P1(2,-6), m2 at point P2(-3,2) and m3 at point P3 (3,4), then

$M_x = \sum_{n=1}^k m_n\cdot y_n = 3\cdot(-6)+4\cdot(2)+3\cdot(4)=2$

$M_y = \sum_{n=1}^k m_n\cdot x_n = 3\cdot(2)+4\cdot(-3)+3\cdot(3)= 3$

Then, the center of Mass is at $(\frac{3}{10},\frac{2}{10})$

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3 years ago