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MariettaO [177]
3 years ago
7

Which half-reaction is most easily oxidized?

Chemistry
2 answers:
timama [110]3 years ago
8 0

Which half-reaction is most easily oxidized?

Answer: Na^+ + e → Na= -2.71 V (D for plato users)


alisha [4.7K]3 years ago
7 0

Answer:

Na+ + e- Na = -2.71 V

Explanation:

We have to remember the nomenclature for redox reactions:

<u>Oxidation</u>:

M~->~M^++e^-

<u>Reduction</u>:

M^+ + e^-~ ->M

So, all the answer options are written as <u>reductions</u>. Therefore the voltage values, in this case, would be the <u>reduction potentials</u>. If we have a higher (<u>positive</u>) potential the compound would be <u>more inclined to a reduction</u> and vice-versa if we have a smaller potential (<u>negative</u>) the compound would be <u>more inclined to oxidation</u>.

In this case, the <u>most negative value</u> is for Na+, so this atom would be more easily <u>oxidized</u>.

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<h2>Answer:</h2>

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Answer:

0.077M

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

2HCl + Mg(OH)2 —> MgCl2 + 2H2O

From the balanced equation above,

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The mole ratio of the base (nB) = 1

Step 2:

Data obtained from the question.

Concentration of base Cb =...?

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Concentration of acid (Ca) = 0.1M

Volume of acid (Va) = 15.4mL

Step 3:

Determination of the concentration of the base, Mg(OH)2.

The concentration of the base can be obtained as follow:

CaVa/CbVb = nA/nB

0.1 x 15.4 /Cb x 10 = 2/1

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Divide both side by 10 x 2

Cb = (0.1 x 15.4) /(10 x 2)

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7 0
3 years ago
Which of the following elements is not likely to form bonds?
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<u>Answer:</u> The amount remained after 151 seconds are 0.041 moles

<u>Explanation:</u>

All the radioactive reactions follows first order kinetics.

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}

where,  

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t = time taken for decay process = 151 sec

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