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MariettaO [177]

3 years ago

7

Which half-reaction is most easily oxidized?

2 answers:

timama [110]3 years ago

8 0

Which half-reaction is most easily oxidized?

Answer: Na^+ + e → Na= -2.71 V (D for plato users)

alisha [4.7K]3 years ago

7 0

Answer:

Na+ + e- Na = -2.71 V

Explanation:

We have to remember the nomenclature for redox reactions:

<u>Oxidation</u>:

$M~->~M^++e^-$

<u>Reduction</u>:

$M^+ + e^-~ ->M$

So, all the answer options are written as <u>reductions</u>. Therefore the voltage values, in this case, would be the <u>reduction potentials</u>. If we have a higher (<u>positive</u>) potential the compound would be <u>more inclined to a reduction</u> and vice-versa if we have a smaller potential (<u>negative</u>) the compound would be <u>more inclined to oxidation</u>.

In this case, the <u>most negative value</u> is for Na+, so this atom would be more easily <u>oxidized</u>.

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"A crosslinked copolymer consists of 57 wt% ethylene (C2H4) repeat units and 43 wt% propylene (C3H6) repeat units. Determine the

ch4aika [34]

Explanation:

Percentage ethylene by weight = 57%

Percentage propylene by weight = 43%

Suppose in 100 grams of polymer:

Mass of ethylene = 57 g

Mass of propylene = 43 g

Moles of ethylene = $\frac{57 g}{28 g/mol}=2.036 mol$

Moles of propylene = $\frac{43g}{42g/mol}=1.024 mol$

1 mole = $N_A =6.022\times 10^{23}$ molecules/ atoms

Units of ethylene = $2.036 mol\times N_A$

Units of propylene = $1.024 mol\times N_A$

a) Fraction of ethylene units:

$=\frac{2.036 mol\times N_A}{2.306 mol\times N_A+1.024 mol\times N_A}=\frac{509}{765}$

b ) Fraction of propylene units:

$=\frac{1.024mol\times N_A}{2.306 mol\times N_A+1.024 mol\times N_A}=\frac{256}{765}$

3 0

3 years ago

Give the number of lone pairs around the central atom and the molecular geometry of XeF4.A)0 lone pairs, tetrahedralB)1 lone pai

vovangra [49]

Answer: 2 lone pairs, square planar

Explanation:

Using the VSEPR ( Valence Shell Electron Pair Repulsion)Theory

To calculate the number of lone pairs electron can be done using the formula;

Number of electrons = ½ (V+N-C+A)

V mean valency of the central atom

N means number of monovalent bonding atoms

C means charge on cation

A means charges on anion

Therefore, to calculate the number of lone pair electron C=A=0;

Number of electrons = ½ (8+4) = 12/2 = 6

Number of bonding pair = 4

Number of lone pairs of electron = 6-4 = 2

The hybridrization of the compound is sp3d2 because the number of electrons around the central atom is 6.

The geometry of the compound is square planar and this is because of the repulsion between the bonding pair of electrons and lone pair of electrons which causes the lone pair of electrons to lie in a perpendicular plane in order to acquire stability.

4 0

3 years ago

Solve for a, b, c, AND d<br> d<br> C<br> 84°<br> 930<br> 970<br> b

olga55 [171]

Answer:

a = 87

b = 83

c = 96

d = 86

5 0

3 years ago

Read 2 more answers

A solid precipitates from a solution, absorbing heat as it does so. a. Yes b. No c. Can't decide with information given.

inn [45]

Answer:

c. Can't decide with information given.

Explanation:

The chemical and physical processes can be classified as endothermic or exothermic. The first one happens when the system absorbs heat, so the temperature of the surroundings will decrease, and the other one happens when the system releases heat, then the temperature of the surrounds will increase.

Precipitation is the formation of a solid in a solution. The process can happen with absorption or release of heat, it depends on the substance. So, with the information given it's impossible to say it.

3 0

3 years ago

If there are 80 liters of argon gas in a piston and the piston expands the gas until its volume is 2000 liters with a pressure o

Mice21 [21]

Answer: The correct answer is A. 11.5 atm. The temperature is held constant at 293 K, therefore, we can use Boyle's Law to determine the initial pressure. Boyle's Law states that there is an inverse relationship between pressure and volume of gases. Therefore, as volume increases, the pressure will decrease and vice versa.

Further Explanation:

Boyle's Law can be mathematically expressed as:

$P_{initial}V_{initial}\ = P_{final}V_{final}$

In this problem, we are given the values:

P(initial) = ?

V(initial) = 80 L

P (final) = 0.46 atm

V (final) = 2000 L

Plugging in these values into the equation:

$P_{initial}(80 \ L) = \ (0.46 \ atm)(2000 \ L)\\P_{initial} \ = \frac{(0.46 \ atm) \ (2000 \ L)}{80 \ L}\\P_{initial}\ = 11.5 atm\\$

The initial pressure was 11.5 atm. Since the volume increased or expanded, the space where the gas particles move is bigger, so the frequency of collisions with the wall of the container and with other particles are effectively decreased. This, therefore, decreases the pressure from 11.5 to 0.46 atm.

Learn More

Learn about Charles' Law brainly.com/question/1421697
Learn about Ideal Gas Law brainly.com/question/6534668
Learn about Gay - Lusaac's Law brainly.com/question/1358307

Keywords: gas, Boyle's Law, Ideal Gas Law

7 0

3 years ago