Answer:
14.53ML
Explanation:
V1=218
V2=?
P2=15p1
USING BOYLE'S LAW
P1V1=P2V2
V2=P1V1/P2=P1(218ML)/15P1
=14.53ML
The answer is coastal upwelling.
The molar concentration of the nitric acid solution was 0.6666 mol/L.
<em>Balanced equation</em>: KOH + HNO_3 → KNO_3 + H_2O
<em>Moles of KOH</em>: 32.33 mL KOH × (1.031 mmol KOH /1 mL KOH)
= 33.33 mmol KOH
<em>Moles of HNO_3</em>: 33.33 mmol KOH× (1 mmol HNO_3/1 mmol KOH)
= 33.33 mmol HNO_3
<em>Concentration of KOH</em>: <em>c </em>= "moles"/"litres" = 33.33 mmol/50.00 mL
= 0.6666 mol/L
Answer:
is the correct answer to the given question.
Explanation:
Given k=6.40 x 10-3 min-1.
According to the first order reaction .
The concentration of time can be written as
![[\ A\ ]\ = \ [\ A_{0}\ ] * e \ ^\ {-kt}](https://tex.z-dn.net/?f=%5B%5C%20A%5C%20%5D%5C%20%3D%20%5C%20%5B%5C%20%20A_%7B0%7D%5C%20%5D%20%20%2A%20e%20%5C%20%5E%5C%20%20%7B-kt%7D)
Here ![[\ A\ ]_{0}](https://tex.z-dn.net/?f=%5B%5C%20A%5C%20%5D_%7B0%7D)
= Initial concentration.
So ![[\ A\ ]_{0}= 0.0314 M](https://tex.z-dn.net/?f=%5B%5C%20A%5C%20%5D_%7B0%7D%3D%200.0314%20M)
Putting this value into the above equation.
=0.211 M
This can be written as
Answer: gain
on:kjn;ijnpyhy8tg6frtgyhuhdr8fitgyg9yug9of5
