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2 years ago

8moles of Na2Cr2O2 is how much mass

Chemistry

1 answer:

Margaret [11]2 years ago

5 0

$\boxed{\boxed{\mathfrak{ 1\: mole \:of \:Na_2Cr_2O_2\: = \:it's \:Gram\: Mol. \: mass}} }$

$\underline{ \mathfrak{ Gram \:molecular \:mass \:of \: \red{ Na_2Cr_2O_2}}}$

= 2 × 23 + 2 × 52 + 2 × 16

= 182 grams

1 mole of $Na_2Cr_2O_2$ weighs = 182 g

8 moles weigh = 8× 182

= $\mathfrak{\blue {\boxed{\underline {1456 \: grams}}}}$

$\mathfrak{\blue {\boxed{\underline {1. 46 \:kg }}}}$

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The equilibrium constant for the reaction is 1.1 x 106 M. HONO(aq) + CN-(aq) ⇋ HCN(aq) + ONO-(aq) This value indicates that

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The given question is incomplete. The complete question is given here :

The equilibrium constant for the reaction is $1.1\times 10^6$ M.

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8moles of Na2Cr2O2 is how much mass​

8moles of Na2Cr2O2 is how much mass