To overcome the forces of attraction
intermolecular forces of attraction for the liquids and gases
Answer:
Tests for unsaturation involves addition across the multiple bonds in the unsaturated compound.
Explanation:
In organic chemistry, we define an unsaturated compound as any compound that contains a double or triple bond. These multiple bonds are also known as pi bonds.
There are two major tests for unsaturation which shall both be discussed here.
The first test for unsaturation is by the use of bromine water. The unknown sample is passed through a solution of bromine water which normally appears reddish brown. The bromine water becomes decolorized due to addition of bromine across the multiple bond. This is a standard test for unsaturation.
Secondly, unsaturated compounds decoulourize a solution of potassium permanganate when passed through it. This alone can not be used as a distinctive test for unsaturation.
Propenoic acid will give a positive test to the both reagents showing that it contains multiple bonds, in this particular instance, a double bond.
Answer:
The mass of sugar used is 427.5 grams.
Explanation:
The formula of common sugar is 
.
Its molar mass of molecule is 342 grams per mole.
The number of moles of sugar used is equal to '1.25'
(NOTE : <em>You can calculate molar mass by adding the mass of all the atoms present in the atom. </em>
<em>Mass of Oxygen (O) = 16 ; Total number of Oxygen atoms present = 11</em>
<em>Mass of Hydrogen (H) =1 ; Total number of Hydrogen Atoms present = 22</em>
<em>Mass of Carbon (C) = 12 ; Total number of Carbon atoms present = 12</em>
<em>Total mass of molecule = 12 × 12 + 1 × 22 + 16 × 11 = 342</em>)
Q = mcΔt
Q = 50 g x 4.184 J/g°c (100 - 20)°C
Q = 16736 J
Explanation:
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