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a_sh-v [17]
3 years ago
10

The rate constant, k, for a first-order reaction is equal to 4.3 × 10-4 s-1. What is the half-life for the reaction? The rate co

nstant, k, for a first-order reaction is equal to 4.3 × 10-4 s-1. What is the half-life for the reaction? 1.9 × 103 s 1.2 × 103 s 1.6 × 103 s 3.0 × 10-4 s
Chemistry
1 answer:
pantera1 [17]3 years ago
4 0

Answer:

1.6 × 10³ s

Explanation:

Let's consider the following generic reaction.

A → B

The rate law is:

rate=k \times [A]^{m}

where,

rate is the reaction rate

k is the rate constant

[A] is the molar concentration of the reactant A

m is the reaction order

When m = 1, we have a first-order reaction. We can calculate the half-life for this reaction using the following expression.

t_{1/2}=\frac{ln2}{k} =\frac{ln2}{4.3 \times 10^{-4}s^{-1} }=1.6 \times 10^{3}s

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<h3>What is the relation between mass & moles?</h3>

Relation between the mass and moles of any substance will be represented as:

  • n = W/M, where
  • W = given mass
  • M = molar mass

Moles of potassium chlorate = 1.66g / 122.5g/mol = 0.0135mole

Given chemical reaction is:

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From the stoichiometry of the reaction, it is clear that:

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