Question

What is the molarity of a 0.40 L Solution with 6.2 g KCl?

Answer 1

Answer:

Molarity of KCl = 0.03M

Explanation:

$Molarity=\frac{W}{GMW} \times \frac{1000}{V(in\,ml)}$

Given

Weight of $KCl$ $=6.2g$

$V=0.40 L=400ml$

Gram Molecular weight$=74.55g$

$Therefore Molarity = \frac{6.2}{74.55}\times{1000}{400}\\ =0.03M$