Answer:
B- Sodium loses an electron.
D- Fluorine gains an electron.
Sodium is oxidized.
Explanation:
The reaction equation is given as:
Na + F → NaF
In this reaction, Na is the reducing agent. It loses an electron and then becomes oxidized. By so doing, Na becomes isoelectronic with Neon.
Fluorine gains the electron and then becomes reduced. This makes fluorine also isoelectronic with Neon.
This separation of charges on the two species leads to an electrostatic attraction which forms the ionic bonds.
Answer:
Li + Cl₂
Explanation:
left side of the arrow are reactants and right side of the arrow are products.
Answer:
0.225 atm
Explanation:
v1=450ml÷1000=0.45l(1l=1000ml)
P1=1
v2=2.00l
p2=?
p1v1=p2v2
p2=p1v1/v2
=1×0.45/2
=0.225
so the answer is first one
The equation is:
Cl₂(aq) + 2 Br⁻(aq) → 2 Cl⁻ (aq) + Br₂(aq)
Oxidation = Loss of electrons
Reduction = gaining of electrons
Oxidizing agent : gain electrons and reduced
Reducing agent : lose electrons and oxidized
For Cl₂ it converted to 2 Cl⁻ so it gains electrons (Reduced) so it oxidize Br⁻ so it considered as Oxidizing agent
So the correct answer is:
C. Chlorine (Cl) is the oxidizing agent because it gains an electron
