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3 years ago

Find the slope of a line perpendicular to y=-2/5x+4/5.

Mathematics

1 answer:

Inga [223]3 years ago

7 0

For two lines to be perpendicular their slopes must be negative reciprocals of one another, mathematically:

m1*m2=-1

In this case, our reference line has a slope of -2/5 so our perpendicular slope must satisfy:

-2m/5=-1

-2m=-5

m=-5/-2

m=5/2

....

The negative reciprocal property can be more easily understood by realizing that the angle of a line is:

tanα=m

α=arctanm

So if one line, A, has a slope of m and the other, B, has a slope of -1/m

A=arctan m, B=arctan -1/m

B-A=90° (feel free to use any value for m that you choose to see that this is true, so if the two lines differ by 90°, they are indeed perpendicular)

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3 years ago

If a polynomial has one root in the form a-V6, it has a second root in the<br> form of a _Vb.

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1 year ago

on the blueprint of the house 44 millimeters represents 8 meters. the length of the living room is 33 millimeters on the bluepri

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2 years ago

Can someone please help me with my maths

Korvikt [17]

Answer:

Step-by-step explanation:

Recall that the "point-slope" form of a linear equation may be expressed as

y = mx + b,

where m is the gradient.

If m is negative, the gradient is negative.

If m is positive, the gradient is positive.

In our case, if we consider option A,

x + 3y = -2 (rearranging)

3y = -x -2

y = (-1/3) x - (2/3)

if we compare this to the general equation at the top, we can see that

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2 years ago

Read 2 more answers

Statistics??? Construct a 95% confidence interval for the population mean. Assume the population has a normal distribution. A sa

antiseptic1488 [7]

Given:
μ = $3120, population mean
σ = $677, population standard deviation.
The population is normally distributed.
n = 20, sample size.

At the 95% confidence level, the confidence interval is
$( \mu - 1.96\frac{\sigma}{ \sqrt{n} } ,\, \mu + 1.96\frac{\sigma}{ \sqrt{n} })$

1.96(σ/√n) = 1.96(677/√20) = 296.71
Th confidence interval for the mean is
($2823.29, $3416.71)

Answer: ($2823.29, $3416.71)

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2 years ago