7/8= 21/24 3/12= 6/24
17 21/24
-12 6/24
______________
5 15/24 = ~5 5/8 ~
Multiply the numerator and denominator by 4+5i
=[(2+3i)(4+5i)]/[(4-5i)(4+5i)]
=[(8-15)+(12+10)i] / [16+25] <span>= [ -7 + 22i ] / [41]
= (-7/41) + (22/41)i </span>
<h3>s³=l,b,h</h3><h3>so,</h3><h3>s³=125</h3>
![s = \sqrt[3]{125}](https://tex.z-dn.net/?f=s%20%3D%20%20%5Csqrt%5B3%5D%7B125%7D%20)
<h3>s=5 and height =5 cubes</h3><h3>hope it helps :-)</h3>
Answer: x=10
Step-by-step explanation:
Answer:
x1 = t, x2 = -t and x3 = 0
Step-by-step explanation:
Given the system of equation
x1 + x2 + x3 = 0 .... 1
x1 + x2 + 9x3 = 0 .... 2
Subtract both equation
x3 - 9x3 = 0
-8x3 = 0
x3 = 0
Substitute x3 = 0 into equation 1
x1 + x2 + 0 = 0
x1+x2 = 0
x1 = -x2
Let t = x1
t = -x2
x2 = -t
Hence x1 = t, x2 = -t and x3 = 0
