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Reptile [31]
3 years ago
10

How do you graph the line on a graph

Mathematics
1 answer:
kotykmax [81]3 years ago
5 0
by starting from the number on the z axis and going up from the y axis
You might be interested in
PLEASE I NEED HELP ASAP! Determine if 9x2 - 42x + 49 can be the area of a square. If so, what would the value of x have to be if
Inga [223]
9x^2 - 42x + 49 is a perfect square trinomial. It factors to (3x - 7)^2
If the area is 64m^2 set this equal to the factors and solve.
(3x - 7)^2 = 64
Take the square root of both sides.
3x - 7 = + - 8
3x - 7 = 8 3x - 7 = - 8
Add 7 to both sides.
3x = 15 3x = - 1
Divide both sides by 3.
x = 5 x = -1/3
x cannot be -1/3 because it would make the length negative.
The answer is x= 5
4 0
3 years ago
Y times 3=9 y =what
Nezavi [6.7K]

Answer: 3 Y=3

Step-by-step explanation:

Y×3=9

3×3=9

You can also check this by rearranging it and dividing 9 by 3.

9÷3=3.

This works for any similar problem.

Example:

Y×4=12 Y=? Y=3

Rearrange it and divide 12 by 4.

12÷4=Y

12÷4=3

So Y×4=12 because 3×4=12

Hope this helps!

6 0
3 years ago
34 &lt; 5x + 9 &lt; 44<br> Inequality
Ksivusya [100]

Answer:

5 < x < 7

Step-by-step explanation:

- Move all terms not containing  x  from the center section of the inequality.

25  <  5 x  <  35

- Divide each term in the inequality by  5 .

5 < 1x < 7

5 < x < 7

i hope this helps :)

5 0
2 years ago
Please explain how and give the answer!
nadezda [96]
The mass of b equals the mass of d so
24(10-x)=6(x+15)
240-24x=6x+90
30x=150
x=5
mass of d is 6(5+15)=6*20=120
mass of c=180-mas of d=180-120=60°
7 0
3 years ago
Read 2 more answers
Find the volume of the solid whose base is the region Ix I Iy I &lt; 1 and whose vertical cross sections perpendicular to the y-
gavmur [86]

Answer:

volume of the solid = \frac{\pi }{3}

Step-by-step explanation:

As given , the region : |x| + |y| \leq 1

when y \geq 0 ,

|x| + y = 1

⇒|x| = 1 - y

when y ≤ 0 ,

|x| - y = 1

⇒|x| = 1 + y

The given region is the rectangle with sides (0, 5) , (0, -5), (5, 0), (-5, 0)

As given , the vertical cross section are semicircle

As we know that the area of semi circle  = \frac{1}{2}\pi  x^{2}

Now,

Volume = \int\limits^0_-1    {\frac{\pi }{2} (1+y)^{2}  } \, dy + \int\limits^1_0    {\frac{\pi }{2} (1-y)^{2}  } \, dy

            = \frac{\pi }{2} (\frac{(1+y)^{3} }{3} ) - \frac{\pi }{2} (\frac{(1-y)^{3} }{3} )

           = \frac{\pi }{6}[1-0] - \frac{\pi }{6}[0-1]

           = \frac{\pi }{6} + \frac{\pi }{6} = 2\frac{\pi }{6} = \frac{\pi }{3}

⇒volume of the solid = \frac{\pi }{3}

4 0
3 years ago
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