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2 years ago

You conduct a hypothesis test for the mean of a population (H0 : p = 5) at the .05 significance level.

Mathematics

1 answer:

Anastaziya [24]2 years ago

8 0

Answer:

The correct option is a)

05; .73; .27 , type 1 error, type 11 error and the power of the test respectively.

Step-by-step explanation:

Alpha is the probability of a type 1 error, given the null hypothesis is true. Therefore alpha= 0.05

Type 11 error is the probability of accepting a false null hypothesis.

Beta= 0.73

The Power of a test is the probability of rejecting the null hypothesis, given it is false

Power= 1- beta

Power= 1-0.73

Power= 0.27

Therefore the type 1 error is 0.05

The type 11 error is= 0.73

The power of the test= 0.27

The right option is a)

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2 years ago

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ratelena [41]

Answer:

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Step-by-step explanation:

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2 years ago

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2 years ago

A bank features a savings account that has an annual percentage rate of 3.5% with interest compounded quarterly. Vanessa deposit

vazorg [7]

Answer:

APY = 0.04 or 4%

Step-by-step explanation:

Given the annual percentage rate of 3.5% that is compounded quarterly, and a principal of $6,500:

We can use the following formula to solve for the annual percentage yield (APY):

$APY = (1 + \frac{r}{n})^n - 1$

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We can plug in the values into the equation:

$APY = (1 + \frac{r}{n})^n - 1$

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2 years ago

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Answer:

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Step-by-step explanation:

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